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miskamm [114]
3 years ago
7

Please help me with my chemistry hw plzzzzz answer my qhestions

Chemistry
1 answer:
tino4ka555 [31]3 years ago
4 0
For 6, celsius to kelvin is simply adding 273.15
So, 297+273.15 = 570.15 kelvin
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What is the concentration of hydroxide in a solution with a pOH of 9.8?
eimsori [14]

Answer:

1.6*10^(-10) M

Explanation:

pOH = 9.8

[OH-]=10^{-log(pOH)} = 10^(-9.8) = 1.6*10^(-10)

6 0
3 years ago
Find the empirical formula of the following compounds:<br> (c) A hydrocarbon with 79.9 mass % carbon
rodikova [14]

The compound is 82.76% C and 17.24% H

In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.

<h3>Describe the empirical formula.</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea.

The simplest whole number ratio of each type of atom in a compound is its empirical formula. It can be determined from data on the mass of each component in a compound or from the composition's proportion.

To learn more about chemical reaction visit:

brainly.com/question/14044066

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8 0
2 years ago
How could an alpha particle pass straight through the metal foil and strike the center of the phosphor screen on the other side
djverab [1.8K]
I think you refer to  Rutherford's Gold Foil Experiment alpha particles pass through because of the enormous amount of empty space inside the atom. 


>>>more details here<<<
to have its trajectory affected the alpha particle has to pass "near" the nucleus to interact with the positive charge of the nucleus.
the fact is that internally the gold atoms are basically empty space and the nucleus represents only a small portion of the entire volume. only few alpha particles pass near the nucleus 

picture added><><**><>< below}{<{>} 
-gio-chealafi- hope this helps you, have a nice rest of the day. ily all!!

8 0
3 years ago
A solution contains 2 meq/ml of kcl. if a 20 ml ampule of this solution is diluted to 1 liter what is the percent strength of th
Serjik [45]

We are given that the concentration of the KCl is 2 meq / mL. Assuming that the ampule also has exactly this concentration, therefore:

 

amount of KCl in ampule = (2 meq / mL) * (20 mL)

amount of KCl in ampule = 40 meq

 

This amount of KCl is now inside a solution of 1 Liter (also equivalent to 1000 mL), therefore the new concentration in the resulting solution is:

new concentration = 40 meq / 1000 mL

new concentration = 0.04 meq / mL

 

Since 0.04 in decimal is 4% in percentage, therefore the strength of the resulting solution is 4% KCl.

7 0
3 years ago
Which characteristic of life Is demonstrated when single -celled organisms split in half, resulting in twice as many organisms a
uysha [10]
The correct answer is B
5 0
3 years ago
Read 2 more answers
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