Answer:
1.6*10^(-10) M
Explanation:
pOH = 9.8
[OH-]=10^{-log(pOH)} = 10^(-9.8) = 1.6*10^(-10)
The compound is 82.76% C and 17.24% H
In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.
<h3>Describe the empirical formula.</h3>
The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea.
The simplest whole number ratio of each type of atom in a compound is its empirical formula. It can be determined from data on the mass of each component in a compound or from the composition's proportion.
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I think you refer to Rutherford's Gold Foil Experiment alpha particles pass through because of the enormous amount of empty space inside the atom.
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to have its trajectory affected the alpha particle has to pass "near" the nucleus to interact with the positive charge of the nucleus.
the fact is that internally the gold atoms are basically empty space and the nucleus represents only a small portion of the entire volume. only few alpha particles pass near the nucleus
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-gio-chealafi- hope this helps you, have a nice rest of the day. ily all!!
We are given that the concentration of the KCl is 2 meq /
mL. Assuming that the ampule also has exactly this concentration, therefore:
amount of KCl in ampule = (2 meq / mL) * (20 mL)
amount of KCl in ampule = 40 meq
This amount of KCl is now inside a solution of 1 Liter (also
equivalent to 1000 mL), therefore the new concentration in the resulting
solution is:
new concentration = 40 meq / 1000 mL
new concentration = 0.04 meq / mL
Since 0.04 in decimal is 4% in percentage, therefore the
strength of the resulting solution is 4% KCl.