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Alexxandr [17]
2 years ago
6

Given 5 Moles of H20. how many moles of O, are produced. Use the following Equation

Chemistry
1 answer:
Otrada [13]2 years ago
7 0

Moles O2 required : 2.5

<h3>Further explanation</h3>

Given

Reaction

2H2+O2->2H2O

Required

Moles of O2

Solution

The reaction coefficient in a chemical equation shows the mole ratio of the reacting compounds (reactants or products)

From the equation, mol ratio of H2O : O2 = 2 : 1, so moles O2 :

= 1/2 x mol H2O

= 1/2 x 5 moles

= 2.5 moles

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Acetylene burns in air according to the following equation: C2H2(g) + 5 2 O2(g) → 2 CO2(g) + H2O(g) ΔH o rxn = −1255.8 kJ Given
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Explanation:

The balanced chemical reaction is,

C_2H_2(g)+\frac{5}{2}O_2(g)\rightarrow 2CO_2(g)+H_2O(g)

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+ n_{H_2O}\times \Delta H_{H_2O})]-[(n_{C_2H_2}\times \Delta H_{C_2H_2})+(n_{O_2}\times \Delta H_{O_2})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-1255.8=[(2\times -393.5)+(1\times -241.8)]-[(1\times \Delta H_{C_2H_2})+(\frac{5}{2}\times 0)]

-1255.8=[(-787)+(-241.8)]-[(1\times \Delta H_{C_2H_2})+(0)]

\Delta H_{C_2H_2}=-227kJ

Therefore, the enthalpy change for C_2H_2 is -227 kJ.

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3 years ago
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