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2 years ago

Given 5 Moles of H20. how many moles of O, are produced. Use the following Equation

Chemistry

1 answer:

Otrada [13]2 years ago

7 0

Moles O2 required : 2.5

<h3>Further explanation</h3>

Given

Reaction

2H2+O2->2H2O

Required

Moles of O2

Solution

The reaction coefficient in a chemical equation shows the mole ratio of the reacting compounds (reactants or products)

From the equation, mol ratio of H2O : O2 = 2 : 1, so moles O2 :

= 1/2 x mol H2O

= 1/2 x 5 moles

= 2.5 moles

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What is the full meaning of DR.HERC.

n200080 [17]

Answer:

It is

D- DEFINE the problem

R-RESEARCH on the problem

H- Carry out a HYPOTHESIS

E- carry out an EXPERIMENT.

R-Analyse the RESULT

C-summarise the CONCLUSION.

Explanation:

Hope it helps.

5 0

3 years ago

Be sure to answer all parts.

tangare [24]

Answer:

(a) cesium bromide (CsBr): 9.15 grams

(b) calcium sulfate (CaSO4): 5.85 grams

(d) lithium dichromate (Li2Cr2O7): 9.88 grams

(e) potassium oxalate (K2C2O4): 7.15 grams

Explanation:

(a) cesium bromide (CsBr):

Molar mass of CsBR = 212.81 g/mol

Number of moles = molarity * volume

Number of moles = 0.100 M *0.43 L

Number of moles = 0.043 moles

Mass of CsBr required = moles * Molar mass

Mass of CsBr required = 0.043 moles * 212.81 g/mol

Mass of CsBr required = 9.15 grams

(b) calcium sulfate (CaSO4):

Molar mass of CaSO4 = 136.14 g/mol

Mass of CaSO4 required = moles * Molar mass

Mass of CaSO4 required = 0.043 moles * 136.14 g/mol

Mass of CaSO4 required = 5.85 grams

(c) sodium phosphate (Na3PO4):

Molar mass of Na3PO4 = 163.94 g/mol

Mass of Na3PO4 required = moles * Molar mass

Mass of Na3PO4 required = 0.043 moles * 163.94 g/mol

Mass of Na3PO4 required = 7.05 grams

(d) lithium dichromate (Li2Cr2O7):

Molar mass of Li2Cr2O7 = 229.87 g/mol

Mass of Li2Cr2O7 required = moles * Molar mass

Mass of Li2Cr2O7 required = 0.043 moles * 229.87 g/mol

Mass of Li2Cr2O7 required = 9.88 grams

(e) potassium oxalate (K2C2O4):

Molar mass of K2C2O4 = 166.22 g/mol

Mass of K2C2O4 required = moles * Molar mass

Mass of K2C2O4 required = 0.043 moles * 166.22 g/mol

Mass of K2C2O4 required = 7.15 grams

7 0

3 years ago

The individual dipole moments in ammonia (NH3) do not cancel each other

kozerog [31]

Answer:

The strongest force that exists between molecules of Ammonia is Hydrogen Bonding.

Explanation:

Hydrogen Bond Interactions are those interactions which are formed between a partial positive hydrogen atom bonded directly to most electronegative atoms (i.e. F, O and N) of one molecule interacts with the partial negative most electronegative atom of another molecule.

Hence, in ammonia the nitrogen atom being more electronegative element than Hydrogen will be having partial negative charge and making the hydrogen atom partial positive. Therefore, the attraction between these partials charges will be the main force of interaction between ammonia molecules.

Other than Hydrogen bonding interactions ammonia will also experience dipole-dipole attraction and London dispersion forces.

4 0

3 years ago

Given the following reaction: NH4SH (s) <--> NH3 (g) + H2S (g) If we start

almond37 [142]

Answer:

D. 0.3 M

Explanation:

NH4SH (s) <--> NH3 (g) + H2S (g)

Initial concentration 0.085mol/0.25L 0 0

Change in concentration -0.2M +0.2 M +0.2M

Equilibrium 0.035mol/0.25 L=0.14M 0.2M 0.2M

concentration

Change in concentration (NH4SH) = (0.085-0.035)mol/0.25L =0.2M

K = [NH3]*[H2S]/[NH4SH] = 0.2M*0.2M/0.14M ≈ 0.29 M ≈ 0.3M

4 0

3 years ago

What is the volume of kristas rock

Elan Coil [88]

Answer:

for what I can see in the picture the volume is 155

Explanation:

7 0

3 years ago

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