To answer this we need to assume that at STP 1 mol of a substance is equal to 22.4 L. We use this data for the calculations.
Statement 1
2 mol HCl (1 mol H2 / 2 mol HCl) = 1 mol H2 thus at STP 22.4 L H2
<em>This statement is false.</em>
Statement 2
1 L Zn (1 mol Zn / 22.4 L Zn) (1 mol H2 / 1 mol Zn) (22.4 L H2 / 1 mol H2) = 1L H2
<em>This statement is true.</em>
Statement 3
65.39 g Zn (1 mol Zn / 65.39 g Zn) (1 mol H2 / 1 mol Zn) = 1 mol H2
<em>This statement is true.</em>
Statement 4
1L HCl (1 mol HCl / 22.4 L HCl)(1 mol H2 / 2 mol HCl) = 0.022 mol H2
<em>This statement is false.</em>
Answer:
Option A) oxygen
Explanation:
Oxygen gas it the electrolysis of an aqueous solution of sodium nitrate which a gas forms at anode it is called the oxygen gas
<em><u>maybe </u></em><em><u>this </u></em><em><u>answer</u></em><em><u> might</u></em><em><u> help</u></em><em><u> u</u></em><em><u> out</u></em>
The volume increases to 1.009 L.
<em>V</em>= <em>V</em>_0 +βΔ<em>T</em>
The thermal expansion coefficient (β) of water changes with temperature, so we must calculate the volume change over small (10 °C) intervals.
20 °C to 30 °C: <em>V</em> = 1 L + 0.000 207 L·°C^(-1) × 10 °C = 1.002 07 L
30 °C to 40 °C: <em>V</em> = 1.002 07 L + 0.000 303 L·°C^(-1)] × 10 °C = 1.005 10 L
40 °C to 50 °C: <em>V</em> = 1.005 10 L + 0.000 385 L·°C^(-1)] × 10 °C = 1.008 95 L
The volume increases by about 9 mL when the temperature increases from 20 °C to 50 °C.
Answer:
Surface Water - water that collects on the surface of the ground. Hope it helped!
Answer: 404.04 kJ.
Explanation:
To calculate the moles, we use the equation:
moles of 
According to stoichiometry :
2 moles of on burning produces = 1036 kJ
Thus 0.78 moles of on burning produces =
Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.
