Considering the margin of error of a confidence interval, it is found that the correct option is:
It would be half as wide.
<h3>What is the margin of error of a confidence interval?</h3>
It is modeled by:
In which:
- s is the standard deviation.
From this, we get that the margin of error is inversely proportional to the square root of the sample size. Then, multiplying the sample size by 4, when it changes from 50 to 200, cuts the margin of error in half, making the interval half as wide.
More can be learned about the margin of error of a confidence interval at brainly.com/question/25890103
I would assume you would do base*width*weight to get your area.
Answer:
15
Step-by-step explanation:
Let n(T) denotes total surveys done i.e. n(T)=140
Let n(A) be the no. of responses to positively to effectiveness i.e. n(A)=71
Let n(B) be the no. of side effects i.e.n(B) =60
Let n(C) be the no. of responses to cost i.e. n(C)= 65
33 responded positively to both effectiveness and side effects
So, n(A∩B)=33
31 to effectiveness and cost
n(A∩C)=31
28 to side effects and cost
n(B∩C)=28
21 to none of the items
So, n(A∪B∪C)=140-21 = 119
we are supposed to find ow many responded positively to all three i.e. n(A∩B∩C)
Formula:
n(A∪B∪C)=n(A)+n(B)+n(C)-n(A∩B)-n(A∩C)-n(B∩C)+ n(A∪B∪C)
119=71+60+65-33-31-28+ n(A∪B∪C)
119=104+ n(A∪B∪C)
119-104= n(A∪B∪C)
15= n(A∪B∪C)
Hence 15 responded positively to all three
Answer:
y=1/2x-2
you write it in y=mx+b form
