Answer:
No photo or graph is there
Explanation:
The large leaves help it survive as they serve as the<u> organ for photosynthesis.</u>
Explanation:
- Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy.
- During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds
- Leaves provide food and air to help a plant stay healthy and grow. Through photosynthesis, leaves turn light energy into food.
- Through pores, or stomata, leaves breathe in carbon dioxide and breathe out oxygen. Leaves also release excess water.
- Most leaves are broad and so have a large surface area allowing them to absorb more light
- A thin shape means a short distance for carbon dioxide to diffuse in and oxygen to diffuse out easily.
- The exchange of oxygen and carbon dioxide in the leaf occurs through pores called stomata.
- Normally stomata open when the light strikes the leaf in the morning and close during the night.
Answer:
The force applied on one wheel during braking = 6.8 lb
Explanation:
Area of the piston (A) = 0.4 
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) = 
⇒ P = 
⇒ P = 16 
This is the pressure inside the cylinder.
Let force applied on the brake pad = 
Area of the brake pad (
)= 1.7
Thus the pressure on the brake pad (
) = 
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P =
⇒ 16 =
⇒ = 16 ×
Put the value of we get
⇒ = 16 × 1.7
⇒ = 27.2 lb
This the total force applied during braking.
The force applied on one wheel = 
= 
= 6.8 lb
⇒ The force applied on one wheel during braking.
Cl2 is the answer. Hope this helps you.
Answer:
r = 5,085 m
Explanation:
The force exerted by on the surface of the Earth on an electron is its weight
W = F = 9.11 10⁻³¹ 9.8
W = 8.9 10⁻³⁰ N
The electric force between an electron and a proton is given by Coulomb's Law
Fe = k q₁ q₂ / r²
Fe = - k q² / r²
They ask us that W = Fe
W = k q² / r²
r = √ k q² / W
Let's calculate
r = √ 8.99 10⁹ (1.6 10⁻¹⁹)² /8.9 10⁻³⁰
r = √ 25.86
r = 5,085 m
Let's look for the relationship of this distance with the harmonic distance
R / R_atomic = 5,085 / 10⁻¹⁰
R / R_Atomic = 5 10¹⁰
We see that this distance is 10¹⁰ times the interatomic distance, so the gravitational attraction force is very small at atomic scale
