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Sladkaya [172]
3 years ago
11

Shelly experiences a backward jolt when the driver starts the school bus. Which of the following explains this phenomenon? A. th

e inertia of Shelly B. the inertia of the bus C. the normal force of the seats on Shelly D. the net force acting on Shelly in a backward direction E. a zero net force acting on Shelly
Physics
2 answers:
JulijaS [17]3 years ago
6 0

A.

Newton's first law. When the bus starts, Shelly is still at rest so she resists motion. (When the bus stops, she'll jolt forward)

Mnenie [13.5K]3 years ago
5 0

Answer: A. The inertia of Shelly

Explanation:

We know from Newton's first law that an object does not changes its state of rest or motion until an unbalanced external force exerts on it. This is also known as law of inertia. Initially Shelly and school bus are in rest state. when the driver starts the school bus and moves forward, Shelly experiences a backward jolt. This is because initially Shelly was in rest state but the bus started moving so she would feel a backward pseudo force.

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Answer:

No photo or graph is there

Explanation:

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2 years ago
How does the physical structure of a plant have<br> Large leaves help it survive?
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The large leaves help it survive as they serve as the<u> organ for photosynthesis.</u>

Explanation:

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3 0
3 years ago
The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.4 square inches. If a force of 6.4 lb
Anit [1.1K]

Answer:

The force applied on one wheel during braking = 6.8 lb

Explanation:

Area of the piston (A) = 0.4 in^{2}

Force applied on the piston(F) = 6.4 lb

Pressure on the piston (P) = \frac{F}{A}

⇒ P = \frac{6.4}{0.4}

⇒ P = 16 \frac{lb}{in^{2} }

This is the pressure inside the cylinder.

Let force applied on the brake pad = F_{1}

Area of the brake pad (A_{1})= 1.7 in^{2}

Thus the pressure on the brake pad (P_{1}) =  \frac{F_{1} }{A_{1} }

When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.

⇒ P = P_{1}

⇒ 16 = \frac{F_{1} }{A_{1} }

⇒ F_{1} = 16 × A_{1}

Put the value of A_{1} we get

⇒ F_{1} = 16 × 1.7

⇒ F_{1} = 27.2 lb

This the total force applied during braking.

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⇒ The force applied on one wheel during braking.

7 0
3 years ago
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4 0
3 years ago
An electron at Earth's surface experiences a gravitational force of magnitude F=(9.11×10−31 kg)⋅(9.8 m/s2). Part A How far away
katrin [286]

Answer:

r = 5,085 m

Explanation:

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          W = 8.9 10⁻³⁰ N

The electric force between an electron and a proton is given by Coulomb's Law

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They ask us that W = Fe

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Let's calculate

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        r = 5,085 m

Let's look for the relationship of this distance with the harmonic distance

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        R / R_Atomic = 5 10¹⁰

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