1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kow [346]
3 years ago
14

A cart loaded with bricks has a total mass of 20.4 kg and is pulled at constant speed by a rope. The rope is inclined at 26.1 ◦

above the horizontal and the cart moves 20.1 m on a horizontal floor. The coefficient of kinetic friction between ground and cart is 0.6 . The acceleration of gravity is 9.8 m/s 2 . What is the normal force exerted on the cart by the floor? Answer in units of N.
Physics
1 answer:
Readme [11.4K]3 years ago
4 0

Answer:

Normal force, N = 154.5 N

Explanation:

Given that,

Total mass of the cart, m = 20.4 kg

Angle of inclination, \theta=26.1^{\circ}

Distance moved, d = 20.1 m

The coefficient of kinetic friction between ground and cart is 0.6

The value of acceleration due to gravity, g=9.8\ m/s^2

Let N is the normal force exerted on the cart by the floor. It is given by :

N=mg-T\ sin\theta

T\ cos\theta=\mu N

T\ cos\theta=\mu (mg-T\ sin\theta)

T\ cos(26.1)=0.6 (20.4\times 9.8-T\ sin(26.1))

T = 103.23 N

So, the normal force is :

N=20.4\times 9.8-103.23\ sin(26.1)

N = 154.5 N

So, the normal force exerted on the cart by the floor is 154.5 N. Hence, this is the required solution.

You might be interested in
Which equation represents a neutralization reaction?
weeeeeb [17]
Is b= acid + base - water + salt.
8 0
2 years ago
Determine the angular velocity of the merry-go-round if a jumps off horizontally in the −n direction with a speed of 2 m/s , mea
lapo4ka [179]

by angular momentum conservation we will have

angular momentum of child + angular momentum of merry go round = 0

angular momentum of child = mvR

m = mass of child

R = radius of child

v = speed = 2 m/s

now let's say moment of inertia of merry go round is I

so we will have

m*2*R + Iw = 0

w = -\frac{2mR}{I}

so merry go round will turn in opposite direction with above speed

6 0
3 years ago
Wayne wants to become a lifeguard. For part of the lifeguard test, he has to float in the pool for five minutes. Why does Wayne
Nastasia [14]

Answer:

D

Explanation:

The gravity is pushing the water downward so Wayne could go down but the water is pushing Wayne to go up which would make him float.

6 0
3 years ago
Determine the magnitude and direction of the resultant force of the following free body diagram.
Papessa [141]

Answer:

The magnitude and direction of the resultant force are approximately 599.923 newtons and 36.405°.

Explanation:

First, we must calculate the resultant force (\vec F), in newtons, by vectorial sum:

\vec F = [(-200\,N)\cdot \cos 60^{\circ}+(400\,N)\cdot \cos 45^{\circ}+300\,N]\,\hat{i} + [(200\,N)\cdot \sin 60^{\circ} + (400\,N)\cdot \sin 45^{\circ}-100\,N]\,\hat{j} (1)

\vec F = 182.843\,\hat{i} + 356.048\,\hat{j}

Second, we calculate the magnitude of the resultant force by Pythagorean Theorem:

\|\vec F\| = \sqrt{(482.843\,N)^{2}+(356.048\,N)^{2}}

\|\vec F\| \approx 599.923\,N

Let suppose that direction of the resultant force is an standard angle. According to (1), the resultant force is set in the first quadrant:

\theta = \tan^{-1}\left(\frac{356.048\,N}{482.843\,N} \right)

Where \theta is the direction of the resultant force, in sexagesimal degrees.

\theta \approx 36.405^{\circ}

The magnitude and direction of the resultant force are approximately 599.923 newtons and 36.405°.

4 0
3 years ago
A rock is thrown vertically upward from some height above the ground. It rises to some maximum height and falls back to the grou
True [87]

Answer:

At the highest point the velocity is zero, the acceleration is directed downward.

Explanation:

This is a free-fall problem, in the case of something being thrown or dropped, the acceleration is equal to -gravity, so -9.80m/s^2. So, the acceleration is never 0 here.

I attached an image from my lecture today, I find it to be helpful. You can see that because of gravity the acceleration is pulled downwards.

At the highest point the velocity is 0, but it's changing direction and that's why there's still an acceleration there.

6 0
3 years ago
Other questions:
  • Technician A states that accidents avoidance is an additional feature on some electronic stability control systems. Technician B
    7·1 answer
  • To test the resiliency of its bumper during low-speed collisions, a 2 840-kg automobile is driven into a brick wall. The car's b
    14·1 answer
  • PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!!!
    7·2 answers
  • The energy flow per unit time per unit area (S) of an electromagnetic wave has an average value of 440 mW/m2. The maximum value
    7·1 answer
  • What is the difference between forming a hypothesis and making a prediction based on the hypothesis?
    14·2 answers
  • Consider a uniformly charged thin-walled right circularcylindrical shell having total charge Q, radiusR, and height h. Determine
    13·1 answer
  • Which two factors does the power of a machine depend on? А. work and distance B.. force and distance C. work and time D. time an
    10·1 answer
  • Which diagram best represents the gravitational forces, F, be-<br> tween a satellite, S, and Earth?
    9·1 answer
  • Sam moves an 800 N wheelbarrow 5 meters in 15 seconds. How much work did he do?
    5·1 answer
  • Kelly Clarkson is running between the Patronas towers in Kuala Lumpur on a tightrope at a speed of 15 m/s. Kelly currently weigh
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!