Answer:
The kinetic energy is 86.6 zepto joules.
Explanation:
Given that,
Number of orbit n =5
We know that,
Bohr's radius for hydrogen atom is
![r = 0.53\times10^{-10}\times n^2\ m](https://tex.z-dn.net/?f=r%20%3D%200.53%5Ctimes10%5E%7B-10%7D%5Ctimes%20n%5E2%5C%20m)
Now, put the value of n in the formula of radius
![r=0.53\times10^{-10}\times5^2](https://tex.z-dn.net/?f=r%3D0.53%5Ctimes10%5E%7B-10%7D%5Ctimes5%5E2)
![r =1.33\times10^{-9}\ m](https://tex.z-dn.net/?f=r%20%3D1.33%5Ctimes10%5E%7B-9%7D%5C%20m)
We need to calculate the kinetic energy
Using formula of kinetic energy
![E_{k}=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{e^2}{2\times r_{s}}](https://tex.z-dn.net/?f=E_%7Bk%7D%3D%5Cdfrac%7B1%7D%7B4%5Cpi%5Cepsilon_%7B0%7D%7D%5Ctimes%5Cdfrac%7Be%5E2%7D%7B2%5Ctimes%20r_%7Bs%7D%7D)
Put the value into the formula
![E_{k}=\dfrac{9\times10^{9}\times(1.6\times10^{-19})^2}{2\times1.33\times10^{-9}}](https://tex.z-dn.net/?f=E_%7Bk%7D%3D%5Cdfrac%7B9%5Ctimes10%5E%7B9%7D%5Ctimes%281.6%5Ctimes10%5E%7B-19%7D%29%5E2%7D%7B2%5Ctimes1.33%5Ctimes10%5E%7B-9%7D%7D)
![E_{k}=8.66\times10^{-20}\ J](https://tex.z-dn.net/?f=E_%7Bk%7D%3D8.66%5Ctimes10%5E%7B-20%7D%5C%20J)
We know that,
![1\ zepto\ joule=1\times10^{-21}\ J](https://tex.z-dn.net/?f=%201%5C%20zepto%5C%20joule%3D1%5Ctimes10%5E%7B-21%7D%5C%20J)
The kinetic energy is
![E_{k}=\dfrac{8.66\times10^{-20}}{1\times10^{-21}}](https://tex.z-dn.net/?f=E_%7Bk%7D%3D%5Cdfrac%7B8.66%5Ctimes10%5E%7B-20%7D%7D%7B1%5Ctimes10%5E%7B-21%7D%7D)
![E_{k}=86.6\ zepto\ Joules](https://tex.z-dn.net/?f=E_%7Bk%7D%3D86.6%5C%20zepto%5C%20Joules)
Hence, The kinetic energy is 86.6 zepto joules.
Answer:
Yes
Explanation:
Yes it is called the refractive index denoted by n
n=sin<i/sin<r
Answer:
0.0613°C
Explanation:
the given parameters are m=15gm=15×10⁻³ V₁=865m/s V₂=534m/s
the bullet moves with different kinetic energies before and after the penetration, therefore
Kinetic energy before - kinetic energy after = 1/2 × m × ( V₁² - V₂²)
=
× 15×10⁻³ × (865² - 534²)
= 3.47 × 10⁻³J
this loss in energy is transferred to the water, therefore
change in temperature = ![\frac{Q}{m C}](https://tex.z-dn.net/?f=%5Cfrac%7BQ%7D%7Bm%20%20C%7D)
where c = heat capacity of water = 4.19 x 10^3
m = mass of water = 13.5 kg
= {3.47 × 10⁻³} / {13.5 x 4.19 x 10^3 }
=0.0613°C
Biotic is the living factors while abiotic is nonliving such as a rock
<span>diminution in the density of something, especially air or a gas.</span>