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vladimir1956 [14]
3 years ago
12

Is this correct> thanks

Physics
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

yes

Explanation:

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Which action would be most important to perform in a controlled experiment? ___A. Design an experiment that is based on previous
ludmilkaskok [199]

Answer:

D. Test a piece of treated iron and a piece of untreated iron under the same conditions.

Explanation:

A controlled experiment is defined as an experiment where the experimenter or the researcher tries to test or experiment his result by changing one variable at a time and keeping the other factors under the same conditions and sees how it effects the result.

The factors which can be changed in an experiment is called its variables.

In the context, testing a piece of treated iron as well as a untreated piece of iron under the same working conditions forms a controlled experiment.

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3 years ago
A natural atom can be negatively charged by
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Answer:

By Gaining Electrons

Explanation:

A nuetral atom is negative when it gains electrons, and it can be positive when it loses electrons.

4 0
3 years ago
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If a 12 kg cat is sitting 5 m up in a tree, how much PE does it have?
Helen [10]

Answer:

588 J

Explanation:

PE (potential energy) = (mass) x (gravity) x (height)

mass = 12 kg

gravity = 9.8m/s^2

height = 5 m

PE = (12) x (9.8) x (5) = 588 J (Joules)

5 0
3 years ago
According to​ Newton's Law of​ Cooling, if a body with temperature Upper T 1 is placed in surroundings with temperature Upper T
lesantik [10]

Answer:

27.22 F.

Explanation:

T ( t ) = T₀ + ( T₁ - T₀)e^{-kt}

T ( t ) = 41 ,  T₀ = 0 , T₁ = 140 , t = 15

Put these values in the equation above

41 = ( 140 - 0 ) e^{-15k}

41/140 = e ^{-15k}

(41/140)^{1/3} = e ^{-5k}

Let after 20 minutes temperature becomes T

T = 0 + 140 e^{-k20}

T / 41 = e^{-5k }

= (41/140)^{1/3}

T = 41 X  (41/140)^{1/3}

= 27.22 F.

7 0
4 years ago
Determine the automobile’s braking distance from 90 km/h when it is going up a 5° incline. (Round the final value to one decimal
NeX [460]

Answer:

366 m

Explanation:

u = 90 km/h = 25 m/s,

theta = 5 degree

acceleration, a = g Sin theta = 9.8 x Sin 5 = 0.854 m/s^2

The final velocity os zero and let the braking distance be s.

Use third equation of motion

v^2 = u^2 - 2 a s

0 = 25 x 25 - 2 x 0.854 x s

s = 366 m

8 0
3 years ago
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