Determine the automobile’s braking distance from 90 km/h when it is going up a 5° incline. (Round the final value to one decimal
place.) The automobile’s braking distance from 90 km/h when it is going up a 5° incline is:
1 answer:
Answer:
366 m
Explanation:
u = 90 km/h = 25 m/s,
theta = 5 degree
acceleration, a = g Sin theta = 9.8 x Sin 5 = 0.854 m/s^2
The final velocity os zero and let the braking distance be s.
Use third equation of motion
v^2 = u^2 - 2 a s
0 = 25 x 25 - 2 x 0.854 x s
s = 366 m
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