Answer:
The half-reaction for the oxidation of the manganese in 
to 
.:
Explanation:
Let us say the medium in which reaction is taking place is an acidic medium. And balancing in an acidic mediums done as;
Step 1: Balance all the atom beside oxygen and hydrogen atom;
Manganese and carbon are balanced.
Step 2: Balance oxygen atom adding water on the required side:
Step 3: Now balance hydrogen atom by adding hydrogen ion on the required side:
Divide 180kg and 90m3 and your density will be 2kg/m3
where, E^{o} (Ag+/Ag) = std. reduction potential of Ag+ = 0.7994 v
and Sn2+/Sn = std. reduction potential of Sn2+ = -0.14 v
Thus, E^{o}cell = 0.7994v - (-0.14v) = 0.9394 v
Now, ΔG^{o} = -nF
,
where, n = number of electrons = 2
F = Faraday's constant = 96500 C
∴ΔG^{o} = 2 X 96500 X 0.9394 = -1.18 X
Now, using Nernst's Equation we have,
![[tex]E_{cell} = 0.9394 - \frac{2.303X298}{2X96500}log \frac{0.0115}{ 3.5^{2} }](https://tex.z-dn.net/?f=%20%5Btex%5DE_%7Bcell%7D%20%3D%200.9394%20-%20%5Cfrac%7B2.303X298%7D%7B2X96500%7Dlog%20%5Cfrac%7B0.0115%7D%7B%203.5%5E%7B2%7D%20%7D%20)
E_{cell} = 0.9765 v
Finally, ΔG = -nFE = -2 X 96500 X 0.9765 = -1.88 X
Answer:
8 meters per second per second
Explanation:
Newton's second law: 
, force = mass multiplied by acceleration.
Therefore 56 / 7 = acceleration = 8
