<h3>
Answer:</h3>
 117.6 Joules 
<h3>
Explanation:</h3>
<u>We are given;</u>
- Force of the dog is 24 N 
- Distance upward is 4.9 m 
We are required to calculate the work done
- Work done is the product of force and distance 
- That is; Work done = Force × distance
- It is measured in Joules.
In this case;
Force applied is equivalent to the weight of the dog.
Work done = 24 N × 4.9 m 
                   = 117.6 Joules 
Hence, the work done in lifting the dog is 117.6 Joules
 
        
        
        
What are you asking here?
        
             
        
        
        
Answer:
The resistance that will provide this potential drop is 388.89 ohms.
Explanation:
Given;
Voltage source, E = 12 V
Voltage rating of the lamp, V = 5 V
Current through the lamp, I = 18 mA
Extra voltage or potential drop, IR =  E- V  
                                                     IR = 12 V - 5 V = 7 V
The resistance that will provide this potential drop (7 V) is calculated as follows:
IR = V
 
Therefore, the resistance that will provide this potential drop is 388.89 ohms.
 
        
             
        
        
        
Answer:
Explanation:
A combination of two controlled variables will make an experiment the most reliable. 
Variables are the values that we take under any circumstance while doing an experiment so that we can keep on changing  and get new results at the end.
It is important to have them in pair so that two values can be kept on changing in terms of any constant condition. This will help to get better results in over all experiment data. 
 
        
             
        
        
        
Answer:
72.1 m
Explanation:
Hello!
When the walker walks west, each block he walks will be of 100 m, so the walker walked 4*100m = 400 m west.
Similarly, when the walker walks south, he walks 20 meters per block, therefore, the walker walked 4*20 m = 80 m south.
Since the directions west and south are perpendicular, the distance between the start ad end point is:
d = √(400^2 + 80^2) m = 407.92 m
However the walker traveled 480 m
Therefore, the walker traveled 480 - 407.9 m = 72.1 m farther than the actual distance