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Lerok [7]
2 years ago
14

What are the similarities and differences for the properties of copper (II) sulphate and copper?

Chemistry
1 answer:
ivann1987 [24]2 years ago
3 0

It is to do with the ionisation of the atom. Copper is a metal, so it will lose electrons. When reacted with a non-metal, it will form an ionic bond.

In copper (I) sulphate, the copper ions have a charge of +1, ie they have lost ONE electron each.

Copper (I) sulphate has the chemical formula Cu2SO4. Each ionic bond involves two Cu+1 ions and a sulphate ion (SO4.

In copper (II) sulphate, the copper ions have a charge of +2, ie they have lost TWO electrons each.

Copper (II) sulphate has the chemical formula CuSO4. Each ionic bond involves a single Cu+2 ion and a sulphate ion (SO4).

So, really, it’s down to the chemical structure and the ionisation of the atom. Apart from the chemistry, copper (I) sulphate a very obscure chemical. Although, after a bit of googling, I have managed to find some info and vendors, it appears that this chemical is rarely seen and doesn’t have many practical uses.

Copper (II) sulphate, on the other hand, is incredibly common. It’s in every school chemistry lab. If someone says “copper sulphate” they will be talking about this chemical, not copper (I) sulphate. In pure form, it is a boring white powder, but when hydrated, it takes on it’s better known blue colour, with blue crystals and blue solution.

Hope this helps.

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How do you do empirical formula
mihalych1998 [28]

Answer:

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Explanation:

Step 1: Obtain the mass of each element present in grams. Element % = mass in g = m.

Step 2: Determine the number of moles of each type of atom present. ...

Step 3: Divide the number of moles of each element by the smallest number of moles. ...

Step 4: Convert numbers to whole numbers.

7 0
2 years ago
A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Evgesh-ka [11]

Answer:

The answer to your question is   P2 = 0.78 atm

Explanation:

Data

Temperature 1 = T1 = 263°K                 Temperature 2 = T2 = 298°K

Volume 1 = V1 = 24 L                             Volume 2 = V2 = 35 L

Pressure 1 = P1 = 1                                  Pressure 2 = P2 = ?

Process

1.- To solve this problem use the Combined gas law

                          P1V1/T1 = P2V2/T2

-Solve for P2

                           P2 = P1V1T2 / T1V2

-Substitution

                          P2 = (1)(24)(298) / (263)(35)

-Simplification

                          P2 = 7152 / 9205

-Result

                          P2 = 0.777

   or                    P2 = 0.78 atm

5 0
3 years ago
Calculate the Ka for the following acid. Determine if it is a strong or weak acid.
vladimir1956 [14]

Answer:

a) Ka= 7.1 × 10⁻⁴; This is a weak acid because the acid is not completely dissociated in solution.

Explanation:

Step 1: Write the dissociation reaction for nitrous acid

HNO₂(aq) ⇄ H⁺(aq) and NO₂⁻(aq)

Step 2: Calculate the acid dissociation constant

Ka = [H⁺] × [NO₂⁻] / [HNO₂]

Ka = 0.022 × 0.022 / 0.68

Ka = 7.1 × 10⁻⁴

Step 3: Determine the strength of the acid

Since Ka is very small, nitrous acid is a weak acid, not completely dissociated in solution.

4 0
3 years ago
Describe the relationship between temperature and kinetic energy.
RSB [31]
Temperature is a measure of the average kinetic energy of the particles in an object.
7 0
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Answer:

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Explanation:

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The formula of liquid water is H₂O.

Calcium Oxide reacts with water and forms Calcium Hydroxide. The Chemical equation is shown below.

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This is a Synthesis reaction because Ca(OH)₂ is synthesized by using Calcium Oxide and water.

The product of this reaction is calcium hydroxide, also known as slaked lime.

Thus, when calcium oxide reacts with water, slaked lime is produced.  

Calcium oxide is also known as lime and is most commonly used for many purposes. It can be used for pH correction of water or for its disinfection (with excess lime).

8 0
3 years ago
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