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sammy [17]
3 years ago
8

When you go camping, you burn wood. Are you contributing to air pollution?

Physics
1 answer:
Jet001 [13]3 years ago
3 0
Yes because of the smoke you are creating in the air
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a bucket of water of mass 20kg is pulled at a constant velocity up to a platform 40 meters above the ground. this takes 10 minut
erma4kov [3.2K]
<span>Taking into account the information above, we know the average mass of the bucket of water may be m=20-5/2=17.5kg. As the bucket of water is pulled at a "constant velocity" the work required to raise the bucket to the platform transformed into the potential energy of the bucket of water. That is why it should be W=mgh=17.5*9.8*40=6860J</span>
5 0
3 years ago
Which formula describes Newton’s second law of motion?
Allushta [10]
Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

6 0
3 years ago
Read 2 more answers
ken, 0.75 kg, moves toward a wall (his path normal to the wall) at 52 m/s. 13.0 ms after he touches the wall he pushes himself o
shtirl [24]

Q: ken, 0.75 kg, moves toward a wall (his path normal to the wall) at 52 m/s. 13.0 ms after he touches the wall he pushes himself off in the opposite direction at 60 m/s. What is the magnitude of the average force the wall exerts on Ken during this rapid maneuver

Answer:

-6461.54 N

Explanation:

From Newton's Fundamental equation,

F = m(v-u)/t.................... Equation 1

Where F = Force exerted in sonic, m = mass of ken, v = final velocity, u = initial velocity, t = time.

Given: m = 0.75 kg, v = - 60 m/s (opposite direction), u = 52 m/s, t = 13 ms = 0.013 s

Substitute into equation 1

F = 0.75(-60-52)/0.013

F = 0.75(-112)/0.013

F = -84/0.013

F = -6461.54 N

Note: The negative sign tells that the force act in opposite direction to the initial motion of ken.

Hence the magnitude of the average force of the wall = -6461.54 N

4 0
3 years ago
You move a 2.5 kg book from a shelf that is 1.2 m above the ground to a shelf that is 2.6 m above the ground. What is the change
Sophie [7]
The change in potential energy of an object is given by
U=mg \Delta h
where
m is the mass of the object
g is the gravitational acceleration
\delta h is the increase in altitude of the object

In our problem, m=2.5 kg is the mass of the book, g=9.81 m/s^2 and 
\Delta h=2.6 m -1.2 m=1.4 m is the increase in altitude of the book, so its variation of potential energy is
U=mg\Delta h=(2.5 kg)(9.81 m/s^2)(1.4 m)=34.3 J
8 0
3 years ago
1.Un conductor este străbătut de un curent electric cu I = 1.
Julli [10]

Answer:

i dont speak spawnish

Explanation:

6 0
3 years ago
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