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3 years ago

If we have less power, we most likely have (2 points)

Physics

1 answer:

iren2701 [21]3 years ago

4 0

<span>. the same amount of work being done over a shorter period of time.</span>

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Find the angle for the third-order maximum for 591 nm wavelength light falling on a diffraction grating having 1460 lines per ce

Marat540 [252]

Answer:

15.32°

Explanation:

We have given the wavelength $\lambda =591nm=591\times 10^{-9}m$

Diffraction grating is 1460 lines per cm

So $d=\frac{10^{-2}}{1460}=6.71\times 10^{-6}m$ (as 1 m=100 cm )

For maximum diffraction

$dsin\Theta =m\lambda$ here m is order of diffraction

So $6.71\times 10^{-6}sin\Theta =3\times 591\times 10^{-9}$

$sin\Theta =0.264$

$\Theta =15.32^{\circ}$

6 0

3 years ago

The work done by an external force to move a -8.50 μC charge from point a to point b is 6.10×10−4 J . If the charge was started

bekas [8.4K]

Answer:

-54.12 V

Explanation:

The work done by this force is equal to the difference between the final value and the initial value of the energy. Since the charge starts from the rest its initial kinetic energy is zero.

$W=\Delta E\\W=\Delta K+\Delta U\\W=K_f+\Delta U\\\Delta U=W-K_f\\\Delta U=6.10*10^{-4}J-1.50*10^{-4}J\\\Delta U=4.60*10^{-4}J$

The change in electrostatic potential energy $\Delta U$ , of one point charge q is defined as the product of the charge and the potential difference.

$\Delta U=qV\\V=\frac{\Delta U}{q}\\V=\frac{4.60*10^{-4}J}{-8.50*10^{-6}C}\\V=-54.12 V$

5 0

4 years ago

The Acorn Insurance Company charges $3.50 for each unit of coverage under a block of 1-year term life insurance policies. The an

ICE Princess25 [194]

Answer:

$175

Explanation:

Insurance premium is expressed as a rate $1000

($3.50 per $1000)

Therefore;

Annual premium= $50000x$3.50/$1000

= $175

8 0

3 years ago

How much voltage is in the primary coil if there are 3200 windings in the

Lesechka [4]

Answer:

Voltage in primary coil is 3.91 V

Explanation:

For transformer we know that the working principle is given as

$\frac{V_1}{V_2} = \frac{N_1}{N_2}$

here we know that

$V_1 [tex] = voltage in primary coil[tex]V_2 = 25 V$

$N_1 = 500$

$N_2 = 3200$

Now we have

$\frac{V_1}{25} = \frac{500}{3200}$

$V_1 = 3.91 V$

8 0

3 years ago

1. Approximately how many people watch the March Madness tournament?

Stolb23 [73]

40 million
1. Approximately how many people watch the March Madness tournament? There are more than 140 million that watch March Madness.

3 0

3 years ago