Question

7. The uranium nucleus contains a charge 92 times that of the proton. If a proton is shot at the nucleus, how large a repulsive force does the proton experience due to the nucleus when it is 1×10-11m from the nucleus? a) 1.1 ×10-4N b) 2.1 ×10-4N c) 1.1 ×10-2N d) 2.1 ×10-2N

Answer 1

Answer:

2.12 x 10^-4 N

Explanation:

charge on uranium nucleus, Q = 92 e

charge on proton, q = e

distance, d = 1 x 10^-11 m

The force between the two charged particles is given by

$F = \frac{KQq}{d^{2}}$

$F = \frac{K\times 92 e \times e}{10^{-22}}$

e = 1.6 x 10^-19 C

$F = \frac{9\times 10^{9}\times 92\times 1.6\times 10^{-19} \times 1.6\times 10^{-19}}{10^{-22}}$

F = 2.12 x 10^-4 N

Thus, the force between the proton and the nucleus of Uranium is 2.12 x 10^-4 N.