Here we go.
My abbreviations; KE = Kinetic Energy; GPE = Gravitational Potential Energy.
So first off, we know the fish has KE right when the bird releases it. Why? Because it has horizontal velocity after released! So let’s calculate it:
KE = 1/2(m)(V)^2
KE = 1/2(2)(18)^2
KE = 324 J
Nice!
We also know that the fish has GPE at its maximum height before release:
GPE = mgh
GPE = (2)(9.81)(5.40)
GPE = 105.95 J
Now, based on the *queue dramatic voice* LAW OF CONSERVATION OF ENERGY, we know all of the initial energy of the fish will be equal to the amount of final energy. And since the only form of energy when it hits the water is KE, we can write:
KEi + GPEi = KEf
(Remember - we found the initial energies before!)
(324) + (105.95) = KEf
KEf = 429.95J
And that’s you’re final answer! Notice how this value is MORE than the initial KE from before (324 J) - this is because all of the initial GPE from before was transformed into more KE as the fish fell (h decreased) and sped up (V increased).
If this helped please like it and comment!
Answer: D. Storage spaces in the cell.
Explanation: The organelle labeled E is called a vacuole and it’s used for storage in both plant and animal cells.
Answer:
P₃ > P₁ > P₂
Explanation:
To rank pressure of the given situation
a) we know
Pressure at height h below
P = ρ g h
density of salt water, ρ = 1029 kg/m³
P₁ = 1029 x 10 x 0.2
P₁ = 2058 Pa
b) density of fresh water, ρ = 1000 kg/m³
P₂ = 1000 x 10 x 0.2
P₂ = 2000 Pa
c) density of mercury, ρ = 13593 kg/m³
P₃ = 13593 x 10 x 0.05
P₃ = 6796.5 Pa
Rank of Pressures from highest to lowest
P₃ > P₁ > P₂
The answer to this question is true
Answer:
the answer is (d + 1) (d + 7)
