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Svetllana [295]
3 years ago
5

A hub a signal that refreshes the signal strength.

Engineering
1 answer:
vekshin13 years ago
7 0

Answer:You are a network engineer. While moving a handheld wireless LAN device, you notice that the signal strength increases when the device is moved from a ...

Explanation:

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A platform and a weight totaling 900 N is held in position by a vertical water jet of 5 cm diameter. Determine the velocity of t
BlackZzzverrR [31]

Answer:

v = 21.409 m/s

Explanation:

Given data:

Total weight of the platform and weight together, W = 900 N

Diameter of the water jet = 5 cm = 0.05 m

Now,

the force exerted by the water jet is balancing the platform

also,

Force exerted by the water jet = ρAv²

where,

ρ is the density of the water = 1000 kg/m³

A is the area of the outlet of the jet = \frac{\pi}{4}d^2=\frac{\pi}{4}(0.05)^2

or

A = 0.00196 m²

v is the velocity of the jet

thus,

W = ρAv²

or

900 = 1000 × 0.00196 × v²

or

v = 21.409 m/s

Hence, the velocity of the jet is 21.409 m/s

7 0
3 years ago
An incremental encoder is rotating at 15 rpm. On the wheel there are 40 holes. How many degrees of rotation would 1 pulse be?
elena-s [515]

Answer:

1 pulse rotate = 9 degree

Explanation:

given data

incremental encoder rotating = 15 rpm

wheel holes = 40

solution

we get here first 1 revolution time

as 15 revolution take = 60 second

so 1 revolution take = \frac{60}{15}

1 revolution take = 4 seconds

and

40 pulse are there for 1 revolution

40 pulse for 360 degree

so 1 pulse rotate is = \frac{360}{40}

1 pulse rotate = 9 degree

3 0
3 years ago
Shear plane angle and shear strain: In an orthogonal cutting operation, the tool has a rake angle = 16°. The chip thickness befo
Oduvanchick [21]

Answer:

shear plane angle Ф = 26.28°

shear strain 2.20

Explanation:

given data

angle = 16°

chip thickness t1 = 0.32 mm

cut yields chip thickness t2 = 0.72 mm

solution

we get here first chip thickness ratio that is

chip thickness ratio = \frac{t1}{t2}    ................. 1

put here value

chip thickness ratio  = \frac{0.32}{0.72}  

chip thickness ratio r = 0.45

so here shear angle will be Ф

tan Ф = \frac{r*cos\alpha }{1-rsin\alpha}   ............2

tan Ф = \frac{0.45*cos16 }{1-rsin16}  

tan Ф = 0.4938

Ф = 26.28°

and

now we get shear strain that is

shear strain r = cot Ф + tan (Ф - α )   ................3

shear strain r  = cot(26.28) + tan (26.28 - 16 )

shear strain r = 2.20

6 0
3 years ago
An engineer who invested very well plans to retire now because she has $2,000,000 in her ORP account. How long will she be able
Ede4ka [16]

Answer:

20 years

Explanation:

You do 2,000,000 ÷ 100,000 but you can simplify that to 20 ÷ 1 = 20

During those 20 years, the profits you earn will be 80,000 since when you do 2,000,000 x 0.04 but you can simplify that to 20,000 x 4 getting 80,000 and that quite doesn't reach 100,000 dollars

8 0
3 years ago
The phasor technique makes it pretty easy to combine several sinusoidal functions into a single sinusoidal expression without us
devlian [24]

Answer:

The phasor technique can't be applied directly in the following cases:

a) 45 sin(2500t – 50°) + 20 cos(1500t +20°)

b) 100 cos(500t +40°) + 50 sin(500t – 120°) – 120 cos(500t + 60°)

c)  -100 sin(10,000t +90°) + 40 sin(10, 100t – 80°) + 80 cos(10,000t)

d)  75 cos(8t+40°) + 75 sin(8t+10°) – 75 cos(8t + 160°)

Explanation:

For a) and c), it is not possible to use the phasor technique, due this technique is only possible when the sinusoidal signals to be combined are all of the same frequency.

This is due to the vector representing a signal is showed as a fixed vector in the graph( which magnitude is equal to the amplitude of the sinusoid and his angle is the phase angle with respect to cos (ωt)), which is rotating at an angular speed equal to the angular frequency of the sinusoidal signal that represents, like a radius that shows a point rotating in a circular uniform movement.

This rotating vector represents a sinusoidal signal, in the form of a cosine (as the real part of the complex function e^{j(wt+\alpha)}), so it is not possible to combine with functions expressed as a sine, even though both  have  the same frequency.

If we look at the graphs of cos (ωt) and sin (ωt) we can say that the sin lags the cos in 90º, so we can say the following:

sin (ωt) = cos (ωt-90º)

This means that in order to be able to represent a sine function  as a cosine, we need to rotate it 90º in the plane clockwise.

This is the reason why before doing this transformation, it is not possible to use the phasor technique for b) and d).

8 0
3 years ago
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