Ivan walks 10 meters west to the water fountain, then runs 2 meters east to his class to avoid a lockout. His displacement would
2 answers:
You might be interested in
Answer:
Final kinetic energy,
Explanation:
It is given that,
Kinetic energy of toy car,
Frictional force, F = 0.5 N
Distance, d = 6 m
We need to find the kinetic energy after this frictional force has acted on it. We know that frictional force is an opposing force. The work done by the toy car is given by :
W = -3 J
We know that the work done is equal to the change in kinetic energy. Let is the final kinetic energy.
So, the final kinetic energy is the toy car is 5 J. Hence, this is the required solution.
Answer:
The maximum shear stress in shaft AB, is 15 MPa
The maximum shear stress in shaft CD, is 45.9 MPa
Explanation:
The formula for a shaft polar moment of inertia, J is given by
J =
Therefore, we have
Where:
D = Diameter of shaft AB = 30 mm = 0.03 m
r = Radius of shaft AB = 15 mm = 0.015 m
∴ = 7.95 × 10⁻⁸ m⁴
and
Where:
D = Diameter of shaft CD = 36 mm = 0.036 m
r = Radius of shaft CD = 18 mm = 0.018 m
Therefore,
= 1.65 × 10⁻⁷ m⁴
Given that the shaft AB and CD are rotated 1.58 ° relative to each other, we have;
1.58 °= rad = 2.76 × 10⁻² rad.
That is = 2.76 × 10⁻² rad.
However
Where:
and
and
= Torque on shaft AB and CD respectively
= Required
= 500 N·m
and
= Length of shafts AB an CD respectively
= 600 mm = 0.6 m
= 900 mm = 0.9 m
G = Shear modulus of the material = 77.2 GPa
Therefore;
=
2.76 × 10⁻² rad =
=
Therefore;
T = 79.54 N.m
Where T = + T
=
Therefore T = 500 - 79.54 = 420.46 N·m
τ =
=
=
= 15 MPa
=
=
= 45.9 MPa