Write the equation for the reaction and balance it. In this case the equation is: 2NaOH + H2SO4 → Na2SO4 + 2H2O
Convert the given amount to moles. Molarity, “M” is moles per liter. The given amount is 25 ml of 1.2 M H2SO4. Since Molarity uses Liters, the volume must be converted from ml to L.
Use the mole ratio in this case 2 moles of NaOH to ! mole of H2SO4
Convert the moles to the required units. In this case the required units are grams. The formula weight in grams er mole.
25 ml H2SO4 * 1L/1000 ml * 1.2 Moles/L * 2 moles NaOH/1 mole H2SO4 * 40 g NaOH/ 1 Mole NaOH
Perform these calculations and you have the answer! Timothy, When doing homework, the answer is NOT the important thing, the METHOD is! These 4 steps, combined with required changes in units will sove ANY stoichiometric problem easily.
Answer:
<h2>9.93 × 10²³ atoms</h2>
Explanation:
The number of atoms of potassium can be found by using the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 1.65 × 6.02 × 10²³
We have the final answer as
<h3>9.93 × 10²³ atoms</h3>
Hope this helps you
Answer:
Volume of solution = 80.5 mL
Explanation:
Given data:
Molarity of solution = 4.50 mol/L
Mass of ethanol = 16.7 g
Volume of solution = ?
Solution:
Volume will be calculated from molarity formula.
Molarity = number of moles / volume in L
Number of moles:
Number of moles = mass/molar mass
Number of moles = 16.7 g/ 46.07 g/mol
Number of moles = 0.3625 mol
Volume of solution:
Molarity = number of moles / volume in L
4.50 mol/L = 0.3625 mol / volume in L
Volume in L = 0.3625 mol /4.50 mol/L
Volume in L = 0.0805 L
Volume in mL:
0.0805 L ×1000 mL/1 L
80.5 mL
The answer depends on what substances you were testing, but here are some ideas.
If all of them were white as in the typical experiment, then color is not very useful. If you were allowed to taste them, then a salty taste would be a helpful clue. If the textures were different, some crystals, like salt or sugar and others powdery, like flour or cornstarch, those properties would be helpful. If some dissolved in water,...
