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bazaltina [42]
3 years ago
7

There are 22 events at an indoor track and field meet. The ratio of track events to field events is 8:3. How many of the events

are track events? Explain how you found your answer.
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0
First, let's look at the ratio.
You also know that for every 8 indoor events, there is 3 field events.
Therefore, the amount of indoor events is 8 on 11 events total, as 8 + 3 = 11
 

Then, let's look at the actual number of events. If there is 22 events total, you need to solve this proportion :

\frac{8}{11} =  \frac{?}{22}
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1. Max has more than 5 carrots (number of carrots Max has = c).​
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c>5

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3 years ago
Greenfield village is spread across 240 acres of land. Only 37% of the land is used for the exhibits, while the rest of the land
Sergeeva-Olga [200]

Answer:

The land which are used for exhibits are <u>89 acres</u> (approximately).

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So, here it is given that land used for exhibits is 37%, and we have to calculate the quantity from the percentage given:

According to question:

37% of 240 acres of land.

\frac{37}{100}\times 240

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5 0
3 years ago
What is the derivative of the following function? f(x) = 4x^6/cos^5(x)
KIM [24]

Answer:

f'(x) = \frac{24x^{5} \cos x + 20x^{6}\sin x}{\cos^{6}x }

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We have to find the derivative of the following function:

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Now, differentiating both sides with respect to x we get,

f'(x) = \frac{\cos^{5}x (24x^{5}) - 4x^{6}(5\cos^{4}x )(- \sin x)}{(\cos^{5}x )^{2}}

⇒ f'(x) = \frac{ 24x^{5} \cos x + 20 x^{6}\sin x}{\cos^{6}x } (Answer)

{Since, we know that, \frac{d(mx^{n} )}{dx} = m \times n x^{(n - 1)} and \frac{d(\cos^{n} x)}{dx} = n \cos^{(n - 1)} x(- \sin x) }

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