Answer:
a.
R-------8/38--------RR
R------9/39--------B-------13/38-------RB
G------17/38--------RG
R-------9/38--------BR
B--------13/39------B-------12/38-------BB
G-------17/38-------BG
R-----9/38--------GR
G---------17/39-------B------13/38-------GB
G------16/38-------GG
b).
- 9 ways
- ways you can select 1 blue are; RB,BR,BG,GB
RB=9/39 × 13/38=3/38
BR= 13/39 × 9/38 =3/38
BG= 13/39 × 17/38=17/114
GB= 17/39 × 13/38=17/114
=3/38 +3/38+17/114+ 17/114 =26/57
- Probability of selecting 2 red markers= RR = 9/39 × 8/38 =12/247
- Probability of selecting a green marker and then a red marker= GR= 17/39×9/38 =51/494
47.47 ................................
No solution because if you distribute -4 to both 2.5y and -3.25 your equation becomes -10y+13-15 1/4=-10y. Then you subtract both 13 and 15 1/4 and get -2.25 so your equation becomes -10y-2.25=-10y. After that you add 10y to both side so your equation becomes -2.25=0 which has no solution.
Answer:
the answer is b) 9.6×10^-6
Answer:
each circle weight 3 grams
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo,
<em>This hanger is in balance. There are two labeled weights of 8 grams and 20 grams.The four circles each have the same weight.</em>
<em>what is the weight of each circle.</em>
My answer:
Let x is the the weight of the circle
Because this hanger is in balance, so we can form the equation:
20 = 8 + 4x
<=> 4x = 20-8
<=> 4x = 12
<=> x = 3
So each circle weight 3 grams