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2 years ago

Am i right?? if not pls help and explain BRAINLIEST be honest

Chemistry

1 answer:

Julli [10]2 years ago

6 0

Answer:

Yes you are right!!!!

Can i have brainliest please and i would be happy to help you again bye luv <3

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True or False, the central atom in a molecule is the one with the highest electron affinity.

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False. Chlorine has the most.

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3 years ago

What behavior of light PROVES that it is a wave? Hint: will this ONLY happen because light is a wave, or could it also be true o

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Answer:

Light changes speed in a glass of water.

Explanation:

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3 years ago

A formal operational thinker and a concrete operational thinker are both presented with three beakers containing red liquid and

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Answer:

The formal thinker would take a systematic approach in the combination of the liquids, thereby eliminating several unnecessary combinations that the concrete thinker would definitely combine.

Explanation:

The formal operational stage in thinking begins when a child gets to the age of 12 and continues to adulthood. The formal operational stage provides an individual with the ability to think abstractly by manipulating ideas in their head without concretely manipulating it. A concrete would have to see something to be able to manipulate any ideas.

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3 years ago

In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe

const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = $10^{-9} m$ .

Hence, 0.283 nm = $0.283 \times 10^{-9} m$

Formula for coulombic energy is as follows.

$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

where, e = $1.6 \times 10^{-19}$ C

$\epsilon_{o}$ = $8.85 \times 10^{-12}$

$U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}$

= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

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3 years ago

What, according to you, are the necessary activities that a penetration tester needs to perform while conducting a penetration t

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3 years ago