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Oliga [24]
3 years ago
15

Calculate the volume of carbon dioxide and water vapour produced and the volume of oxygen remaining, when 20.0 dm3 of propane re

acts with 120.0 dm3 of oxygen. All gas volumes are measured at the same temperature and pressure.

Chemistry
1 answer:
laiz [17]3 years ago
6 0

Answer:

80cm3 of water, and 60cm3 carbon IV oxide is formed while 20cm3 of oxygen is left unreacted.

Explanation:

From Gay-Lussac's law, there are five volumes of oxygen, 1 volume if propane, 4 volumes of water and three volumes of CO2. Applying this shows the reacting volumes as we have in the image attached, hence the volumes left after reaction.

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A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h
frosja888 [35]

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]

Where;

\frac{f_2}{f_1}  is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1}  = 10^{0.7289}\\\\\frac{f_2}{f_1}  = 5.356

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

5 0
3 years ago
56.5 g of sodium nitrate is dissolved in water to make 627 g of solution . what is the percent sodium nitrate in the solution
Tamiku [17]

Answer:

9.01%

Explanation:

The following data were obtained from the question:

Mass of sodium nitrate, NaNO3 = 56.5g

Mass of solution = 627g

The percentage composition of sodium nitrate, NaNO3 in the solution can be obtained as follow:

Percentage composition of NaNO3 = Mass of NaNO3/mass of solution x 100

Percentage composition of NaNO3 = 56.5/627 x 100 = 9.01%

Therefore, the percentage composition of sodium nitrate, NaNO3 in the solution is 9.01%

8 0
3 years ago
Read 2 more answers
Can someone easily explain to me how to do reaction rates?
iVinArrow [24]

Explanation:

Reaction rate is a measure of speed of a chemical reaction.

Usually, based on rates, reactions can be divided into two parts:

  • Slow reactions which usually takes a long time.
  • Fast reactions which takes place completely in seconds or microseconds.

Reaction rate can be defined as a change in the concentration of a reactant or product per unit time:

      The unit is  mol dm⁻³ s⁻¹

Reaction rate = \frac{change in concentration of a reactant and product}{time taken }

The measurement of the reaction rate is based on the disappearance of a reactant or appearance of a product with increasing reaction time.

Learn more:

Reaction rate brainly.com/question/9642960

#learnwithBrainly

5 0
3 years ago
How do you percipitate things from solution to telluric acid?
mario62 [17]
I think this is your answer

4 0
4 years ago
What is another name for organic sedimentary rock?
Morgarella [4.7K]
Hello there,
Rocks that were once swampy sediments or peat beds contain carbon and are black, soft, and fossiliferous<span>.(also known as organic sedimentary rock)
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Hope this helps :)

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3 years ago
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