Calculate the volume of carbon dioxide and water vapour produced and the volume of oxygen remaining, when 20.0 dm3 of propane re
acts with 120.0 dm3 of oxygen. All gas volumes are measured at the same temperature and pressure.
1 answer:
Answer:
80cm3 of water, and 60cm3 carbon IV oxide is formed while 20cm3 of oxygen is left unreacted.
Explanation:
From Gay-Lussac's law, there are five volumes of oxygen, 1 volume if propane, 4 volumes of water and three volumes of CO2. Applying this shows the reacting volumes as we have in the image attached, hence the volumes left after reaction.
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Answer:
Liming reagent in the given reaction is oxygen.
Explanation:
Mass of octane = 12.85 g
Mass of oxygen = 7.46 g
Molar mass of octane = 114.23 g/mol
Molar mass of oxygen = 32
According to the reaction, 2 moles of octane requires 25 moles of O2
so, 0.1125 moles of octane requires of oxygen.
but only 0.2331 mol of oxygen is present.
Hence, oxygen is the limiting reagent