List three differences between the earth 240 million years ago and the present earth.

An analytical chemist is titrating of a solution of propionic acid with a solution of 224.9 ml of a 0.6100M solution of propioni

Svetllana [295]

Answer: The pH of acid solution is 4.58

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For KOH:

Molarity of KOH solution = 1.1000 M

Volume of solution = 41.04 mL

Putting values in equation 1, we get:

$1.1000M=\frac{\text{Moles of KOH}\times 1000}{41.04}\\\\\text{Moles of KOH}=\frac{1.1000\times 41.04}{1000}=0.04514mol$

For propanoic acid:

Molarity of propanoic acid solution = 0.6100 M

Volume of solution = 224.9 mL

Putting values in equation 1, we get:

$0.6100M=\frac{\text{Moles of propanoic acid}\times 1000}{224.9}\\\\\text{Moles of propanoic acid}=\frac{0.6100\times 224.9}{1000}=0.1372mol$

The chemical reaction for propanoic acid and KOH follows the equation:

$C_2H_5COOH+KOH\rightarrow C_2H_5COOK+H_2O$

Initial: 0.1372 0.04514

Final: 0.09206 - 0.04514

Total volume of solution = [224.9 + 41.04] mL = 265.94 mL = 0.26594 L (Conversion factor: 1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[acid]})$

$pH=pK_a+\log(\frac{[C_2H_5COOK]}{[C_2H_5COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of propanoic acid = 4.89

$[C_2H_5COOK]=\frac{0.04514}{0.26594}$

$[C_2H_5COOH]=\frac{0.09206}{0.26594}$

pH = ?

Putting values in above equation, we get:

$pH=4.89+\log(\frac{(0.04514/0.26594)}{(0.09206/0.26594)})\\\\pH=4.58$

Hence, the pH of acid solution is 4.58

7 0

3 years ago

A) Calculate the pH of a 2.0x10-4 M solution of aniline hydrochoride, C6H5NH3Cl.

igor_vitrenko [27]

Given the concentration of aniline hydrochloride is $2.0 *10^{-4} M$

Aniline hydrochloride is the conjugate acid of aniline a weak base.

pH can be calculated from $pK_{a}$ anilinium ion the conjugate acid of aniline.

8 0

3 years ago

Read 2 more answers

Show the difference between a saturated hydrocarbon and an unsaturated hydrocarbon.

harkovskaia [24]

Saturated hydrocarbons consists of C-C single bond whereas Unsaturated hydrocarbons consists C-C double/triple bond.

4 0

2 years ago

Balance the following chemical equation. CCl4 -> ___ C+ ___ Cl2

Bingel [31]

Answer:

Explanation:

CCl4 => C + 2Cl2

6 0

2 years ago

Bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter

Alisiya [41]

Answer:Hence, the bond length in HCl is 125 pm.

Explanation:

Bond length : It is an average distance between the nuclei of two bonded atoms in a molecule.

Also given that bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter-nuclear distance between the two atoms when the potential energy of the system reaches its lowest value. Beyond this if atoms come closer to each other then their will be repulsion between them.

So, the bond length between the Hydrogen and Chlorine atom in HCl molecule is :

$Bond length=radius _{hydrogen}+radius_{chlorine}=25pm+100pm=125pm$

Hence, the bond length in HCl is 125 pm.

5 0

3 years ago

Read 2 more answers