A child walks 5.0 meters north, then 4.0 meters east, and finally 2.0 meters south. what is the magnitude of the resultant displ
acement of the child after the entire walk
2 answers:
Answer:
Resultant displacement of the child is 5 m.
Explanation:
It is given that, a child walks 5.0 meters north, then 4.0 meters east, and finally 2.0 meters south.
We have to find the magnitude of displacement of the child after the entire walk. The attached figure shows entire journey of the child. Displacement of an object is equal to the shortest path covered by it. Here, AM shows the net displacement. It can be calculated using Pythagoras theorem as :
Since, AB = 5 m So, OA = 3 m and BC = OM = 4 m
⇒ AM = 5 m
Hence, the resultant displacement of the child after the entire walk is 5 m.
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Answer:
v₃ = 3.33 [m/s]
Explanation:
This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.
In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.
where:
m₁ = mass of the car = 1000 [kg]
v₁ = velocity of the car = 10 [m/s]
m₂ = mass of the truck = 2000 [kg]
v₂ = velocity of the truck = 0 (stationary)
v₃ = velocity of the two vehicles after the collision [m/s].
Now replacing: