Answer:
164.4 L
Explanation:
use charles' law formula Volume 1 over Temp. 1 equaled to Volume 2 over Temp. 2
Answer:
ΔHrxn = -635.14kJ/mol
Explanation:
We can make algebraic operations of reactions until obtain the desire reaction and, ΔH of the reaction must be operated in the same way to obtain the ΔH of the desire reaction (Hess's law). Using the reactions:
(1)Ca(s) + 2 H+(aq) → Ca2+(aq) + H2(g) ΔH = 1925.9 kJ/mol
(2) 2H2(g) + O2 g) → 2 H2O(l) ΔH = −571.68 kJ/mole
(3) CaO(s) + 2 H+(aq) → Ca2+(aq) + H2O(l) ΔH = 2275.2 kJ/mole
Reaction (1) - (3) produce:
Ca(s) + H2O(l) → H2(g) + CaO(s)
ΔH = 1925.9kJ/mol - 2275.2kJ/mol = -349.3kJ/mol
Now this reaction + 1/2(2):
Ca(s) + ½ O2(g) → CaO(s)
ΔH = -349.3kJ/mol + 1/2 (-571.68kJ/mol)
<h3>ΔHrxn = -635.14kJ/mol</h3>
boron, carbon, nitrogen, oxygen and flourine families in addition to the noble gases.
_________________________________________________________
also to answer the 'hello guys what is good!':nothin u?
__________________________________________
o0o0o0o0o0o0o0o0o0o0o0o0o0o0o0o0o0o0o0o0
Answer:
I think it's C or D Sorry if I'm Wrong
Explanation:
it just makes the most sense to me
Answer:
Yes
2Ag + Cu(No3)2 -----(heat) ----- Cu + 2Agno3
When heat energy is passed through Cu(No3)2 then the reverse reaction will occur