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nasty-shy [4]
3 years ago
8

Electromagnetic induction means that moving a magnet through a loop of wire creates an electric current.

Physics
2 answers:
Stels [109]3 years ago
7 0

Answer:

false

Explanation:

MAVERICK [17]3 years ago
4 0
False. An Electromagnetic induction is the production of an electromotive force across an electrical conductor in a changing magnetic field.
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Light in air enter crown glass (n = 1.52) at an angle of 35 degrees. What is the refracted angle?
Dovator [93]

Answer:

22.17 degree

Explanation:

n = 1.52

Angle of incidence, i = 35 degree

Let the angle of refraction is r.

use the Snell's law

n = Sin i / Sin r

Sin r = Sin i / n = Sin 35 / 1 .52

Sin r = 0.37735

r = 22.17 degree

Thus, the ray is refracted at an angle of 22.17 degree.

8 0
3 years ago
Which formula can be used to calculate the horizontal displacement not of a horizontally launched projectile
svetlana [45]
<span>If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field. it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection. There are a number of ways that you could find a horizontally displaced object. You could for example just look.</span>
8 0
3 years ago
At a pressure of one atmosphere oxygen boils at −182.9°C and freezes at −218.3°C. Consider a temperature scale where the boiling
Gelneren [198K]

Answer: -254.51°O

Explanation:

Ok, in our scale, we have:

-182.9°C corresponds to 100° O

-218.3°C corresponds to 0°

Then we can find the slope of this relation as:

S = (100° - 0°)/(-182.9°C - (-218.3°C)) = 2.82°O/°C

So we can have the linear relationship between the scales is:

Y = (2.82°O/°C)*X + B

in this relation, X is the temperature in Celcius and Y is the temperature in the new scale.

And we know that when X = -182.9°C, we must have Y = 0°O

then:

0 = (2.82°O/°C)*(-182.9°C) + B

B = ( 2.82°O/°C*189.9°C) = 515.778°O.

now, we want to find the 0 K in this scale, and we know that:

0 K = -273.15°C

So we can use X =  -273.15°C in our previous equation and get:

Y = (2.82°O/°C)*(-273.15°C) + 515.778°O = -254.51°O

5 0
3 years ago
Define the terms ‘latent heat of vaporization’ and ‘phase change’ in your own words. What is the commonly accepted value of the
olganol [36]

Answer:

Latent Heat of Vaporization of Nitrogen is 2.7928 KJmol^{-1}

Explanation:

• We have learned that adding thermal energy by heat increases the temperature of a substance.

• But surprisingly, there are situations where adding energy does not change the temperature of a substance at all. Instead, the additional thermal energy acts to loosen bonds between molecules or atoms and causes a phase change.

• Because this energy enters or leaves a system during a phase change without causing a temperature change in the system, it is known as latent heat (latent means hidden).

• Latent heat of vaporization is a physical property of a substance.

• It is defined as the heat required to change one mole of liquid at its boiling point under standard atmospheric pressure. It is expressed as kg/mol or kJ/kg.

• When a material in liquid state is given energy, it changes its phase from liquid to vapor; the energy absorbed in this process is called heat of vaporization.

• Latent Heat of Vaporization of Nitrogen is 2.7928 KJmol^{-1}

7 0
3 years ago
A lamp has the shape of a parabola when viewed from the side. The lamp is centimeters wide and centimeters deep. How far is the
andrew-mc [135]

The question is not complete so i have attached it.

Answer:

The light source is 2 cm from the bottom of the lamp

Explanation:

From the attached image, we can see that the parabola opens up with its vertex at the origin.

Now, the standard form of equation for a parabola is:

x² = 4ay

Looking at the parabola in the attachment, the top right edge of the lamp has a coordinate of (12,18)

Thus, we have;

12² = 4a(18)

144 = 72a

a = 144/72

a = 2

Looking at the parabola again, the line of symmetry is at x = 0

Thus, axis of symmetry is at x = 0.

Thus, focus is at (0, 2)

So, if the light source is placed at the focus, the distance of the light source from the bottom of the lamp is 2 cm

8 0
3 years ago
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