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weqwewe [10]
3 years ago
7

Calculate the work done by applying a 125 N force to the right on a 65.0 kg sled to displace

Physics
1 answer:
Elanso [62]3 years ago
5 0
W=fd
W= (125N) (3.5m)
W= 437.5 J
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Which types of electromagnetic waves have higher frequencies then the waves that make up ultraviolet light?
TiliK225 [7]

Answer: Visible light makes up just a small part of the full electromagnetic spectrum. Electromagnetic waves with shorter wavelengths and higher frequencies include ultraviolet light, X-rays, and gamma rays.

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4 years ago
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The work function of a metal surface is 4.80 × 10-19 J. The maximum speed of the electrons emitted from the surface is vA = 7.7
poizon [28]

Answer:

\lambda_A=2.65177\times 10^{-7}\ m

\lambda_B=3.32344\times 10^{-7}\ m

Explanation:

h = Planck's constant = 6.63\times 10^{-34}\ m^2kg/s

c = Speed of light = 3\times 10^8\ m/s

m = Mass of electron = 9.11\times 10^{-31}\ kg

W_0 = Work function = 4.8\times 10^{-19}\ J

v_A = Velocity of A particle = 7.7\times 10^5\ m/s

v_B = Velocity of B particle = 5.1\times 10^5\ m/s

The wavelength is given by

\lambda=\frac{hc}{\frac{1}{2}mv^2+W_0}

\lambda_A=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(7.7\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_A=2.65177\times 10^{-7}\ m

The wavelength \lambda_A=2.65177\times 10^{-7}\ m

\lambda_B=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(5.1\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_B=3.32344\times 10^{-7}\ m

The wavelength \lambda_B=3.32344\times 10^{-7}\ m

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4 years ago
Question 18 of 25
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Endothermic, because the reactants are lower in energy (C)

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The answers to these questions!
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3 years ago
A machine in an ice factory is capable of exerting 3.00x10^2 N of force to pull a large block of ice up a slope. The block weigh
aivan3 [116]

Answer:

1.41 °

Explanation:

From machine,

The formula for the efficiency of machine is

E(%) = (M.A/V.R)×100................. Equation 1

Where E(%) = Percentage Efficiency of the machine, M.A = Mechanical Advantage of the machine, V.R = Velocity ratio of the machine.

Note: A slope forms an an inclined plane with the horizontal

Make V.R the subject of the equation

V.R = 100M.R/E(%)................. Equation 2

But,

M.A = L/E......................... Equation 3

Where Load, E = Effort.

Given: E = 3.00×10² N, L = 1.22×10⁴ N

Substitute into equation 3

M.A = 1.22×10⁴ / 3.00×10²

M.A = 40.7.

Note: Assuming no friction means that the efficiency of the inclined plane(slope) = 100 %

Hence, E(%) = 100 %

Substitute into equation 2

V.R = 100(40.7)/100

V.R = 40.7.

The velocity of an inclined plane is

V.R = 1/sin∅........................... Equation 4

Where ∅ = maximum angle that the slope makes with the horizontal.

make ∅ the subject of the equation

∅ = sin⁻¹(1/V.R)................... Equation 5

Substitute the value of V.R into equation 5

∅ = sin⁻¹(1/40.7)

∅ = sin⁻¹(0.0246)

∅ = 1.41 °

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4 years ago
Read 2 more answers
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