Calculate the work done by applying a 125 N force to the right on a 65.0 kg sled to displace

If i eat myself will I get twice as big or disappear completely?

mihalych1998 [28]

Answer:

Disappear quickly

Explanation:

7 0

3 years ago

The angular velocity of the disk is defined by ω = ( 5 t 2 + 2 ) r a d / s , where t is in seconds. Determine the magnitudes of

ohaa [14]

Answer

given,

Assume radius of the disk be = 0.8 m

angular velocity of disk

ω = ( 5 t² + 2 ) r a d / s

magnitude of velocity and acceleration = ?

At the instant of time, t = 0.5 s

ω = ( 5 x (0.5)² + 2 ) r a d / s

ω = 3.25 r a d / s

$\alpha = \dfrac{d\omega}{dt}$

$\alpha = \dfrac{d}{dt}( 5 t² + 2)$

$\alpha =10 t$

$\alpha =10\times 0.5$

α = 5 rad/s²

velocity

v = ω r

v = 3.25 x 0.8

v = 2.6 m/s

tangential acceleration

$a_t = \alpha r$

$a_t =5 \times 0.8$

$a_t =4\ m/s^2$

normal acceleration

$a_n = \omega^2\ r$

$a_n = 3.25^2\times 0.8$

$a_n =8.45 \m/s^2$

$a = \sqrt{a_n^2 + a_t^2}$

magnitude of the acceleration

$a = \sqrt{8.45^2 + 4^2}$

a = 9.35 m/s²

6 0

3 years ago

How is pressure related to force and surface area

kherson [118]

Pressure is Force per Unit Area.Pressure is the force on an object that is spread over a surface area. The equation for pressure is the forcedivided by the area where the force is applied.

7 0

3 years ago

A spherical shell of radius 3.59 cm and a cylinder of radius 7.22 cm are rolling without slipping along the same floor. The two

vampirchik [111]

Answer:

(ω₁ / ω₂) = 1.9079

Explanation:

Given

R₁ = 3.59 cm

R₂ = 7.22 cm

m₁ = m₂ = m

K₁ = K₂

We know that

K₁ = Kt₁ + Kr₁ = 0.5*m₁*v₁²+0.5*I₁*ω₁²

if

v₁ = ω₁*R₁

and

I₁ = (2/3)*m₁*R₁² = (2/3)*m*R₁²

∴ K₁ = 0.5*m*ω₁²*R₁²+0.5*(2/3)*m*R₁²*ω₁² (I)

then

K₂ = Kt₂ + Kr₂ = 0.5*m₂*v₂²+0.5*I₂*ω₂²

if

v₂ = ω₂*R₂

and

I₂ = 0.5*m₂*R₂² = 0.5*m*R₂²

∴ K₂ = 0.5*m*ω₂²*R₂²+0.5*(0.5*m*R₂²)*ω₂² (II)

∵ K₁ = K₂

⇒ 0.5*m*ω₁²*R₁²+0.5*(2/3)*m*R₁²*ω₁² = 0.5*m*ω₂²*R₂²+0.5*(0.5*m*R₂²)*ω₂²

⇒ ω₁²*R₁²+(2/3)*R₁²*ω₁² = ω₂²*R₂²+0.5*R₂²*ω₂²

⇒ (5/3)*ω₁²*R₁² = (3/2)*ω₂²*R₂²

⇒ (ω₁ / ω₂)² = (3/2)*R₂² / ((5/3)*R₁²)

⇒ (ω₁ / ω₂)² = (9/10)*(7.22/ 3.59)²

⇒ (ω₁ / ω₂) = (7.22/ 3.59)√(9/10)

⇒ (ω₁ / ω₂) = 1.9079

8 0

3 years ago

The following force diagram represents Newton’s Third Law of Motion:

Julli [10]

Answer:

FALSE.

Explanation:

Newton's third law states that :

Every action has equal and opposite reaction
That is , the magnitude is the same but the directions are opposite
The action reaction forces DONOT operate on the same body.

For example ,

If a block is kept on the ground , the action force is the normal force acting on it due to the ground. BUT , NOTE THAT : the reaction force isn't the gravitational force on the body ! It is the normal force acting on the ground due to the block !

Thus,

we conclude that action and reaction forces donot act on the same body and therefore , this case has the answer : FALSE

4 0

3 years ago