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ehidna [41]
3 years ago
7

Your lab has two pressurized gas cylinders, each containing a different gas. describe an experiment that could be used to determ

ine whether each gas is less dense than air.
Physics
1 answer:
Papessa [141]3 years ago
8 0
The easiest way is to fill two very light globes, each with a different gas.

Blow globe 1 with gas from the cylinder marked with label 1, and blow glove 2 with gas from the cylinder marked with label 2.

If a globe ascends in the air, it is because its gas is less dense than air.

Inflate the globes quite enough to be sure that the mass of the rubber of the globe is not important relative to the mass of  gas and so it does not change the results. If you obtain a result where the globe does not have a cliea ascending or descending motion, you can inflate more the globe and it shouuld start to rise if the gas really is less dense than air.
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A tennis racket strikes a tennis ball with a force of 100 N. With what force
viva [34]

Answer:

-100N

Explanation:

Newton's third law of motion states that to every force exerted on one body, there is an equal and opposite force. This means that if object A exerts an ACTION force on B, there is a force called REACTION FORCE, which is equal and opposite, exerted on A by B.

The action and reaction forces are equal in size/magnitude but opposite in direction. In this case where a tennis racket strikes a tennis ball with a force (action force) of 100N, the ball will strike the racket with a reaction force of -100N.

F(RB) = -F(BR)

8 0
3 years ago
A solid weighs 16.5N on the surface of the moon. The force of gravity on the moon is 1.7N/Kg.
Fiesta28 [93]

Answer:

mass = 9.7 kg

Explanation:

Weight = Mass x Acceleration due to gravity (g)

16.5 = mass x 1.7

mass = \frac{16.5}{1.7} = 9.7 kg

3 0
2 years ago
I WILL MARK BRAINLIEST TO WHOEVER GETS THIS CORRECT
Veseljchak [2.6K]

Answer:

If south-east Texas is where H then it is C, but if not the answer is A.

6 0
2 years ago
Read 2 more answers
Please help! thank you​
BlackZzzverrR [31]

Answer:

poor, too precise

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good

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Explanation:

8 0
3 years ago
A child's top is held in place upright on a frictionless surface. The axle has a radius of ????=3.21 mm . Two strings are wrappe
tekilochka [14]

Answer:

Angular momentum, L=6.47\times 10^{-3}\ m

Explanation:

It is given that,

Radius of the axle, r=3.21\ mm=3.21\times 10^{-3}\ m

Tension acting on the top, T = 3.15 N

Time taken by the string to unwind, t = 0.32 s

We know that the rate of change of angular momentum is equal to the torque acting on the torque. The relation is given by :

\tau=\dfrac{dL}{dt}

Torque acting on the top is given by :

\tau=F\times r

Here, F is the tension acting on it. Torque acting on the top is given by :

\tau=2F\times r

2T\times r=\dfrac{L}{t}

L=2T\times r \times t

L=2\times 3.15\times 3.21\times 10^{-3}\times 0.32

L=6.47\times 10^{-3}\ m

So, the angular momentum acquired by the top is 6.47\times 10^{-3}\ m. Hence, this is the required solution.

7 0
3 years ago
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