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irga5000 [103]
3 years ago
12

Describe the relationship between the forces of attraction and the kinetic energy of particles in a solid, a liquid and a gas

Physics
1 answer:
mel-nik [20]3 years ago
5 0

Answer:

Described below

Explanation:

1) Solids: In solids, the strong attractive forces between the particles ensure that the particles are packed tightly enough and this means little or no movement between each other. However, when they experience vibration which has relationship with the kinetic energy between them

2) Liquids; In liquids due to the lesser forces of attraction between the particles, it means they tend to glide over each another but however, toward the bottom of the container they will settle. This means that the attractive forces between the liquid particles are barely strong enough to hold onto a specific volume. However, they are not strong enough to keep the molecules from sliding over one other.

3) Gases; In gases, there is almost no existing attractive force in most cases and as a result we can say the kinetic energy of the gas molecules is always greater than the attractive force between them and they are therefore far apart from each other and also move independent of each other.

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What atoms has most mass?<br>​
Ipatiy [6.2K]
Oganesson has the highest atomic number and highest atomic mass of all know elements.
4 0
2 years ago
A well lagged copper calorimeter of mas 120g contains 70g of water and 10g ice both at 0°C . Dry steam at 100°C is passed in unt
Lina20 [59]

Answer:

7.6 g

Explanation:

"Well lagged" means insulated, so there's no heat transfer between the calorimeter and the surroundings.

The heat gained by the copper, water, and ice = the heat lost by the steam

Heat gained by the copper:

q = mCΔT

q = (120 g) (0.40 J/g/K) (40°C − 0°C)

q = 1920 J

Heat gained by the water:

q = mCΔT

q = (70 g) (4.2 J/g/K) (40°C − 0°C)

q = 11760 J

Heat gained by the ice:

q = mL + mCΔT

q = (10 g) (320 J/g) + (10 g) (4.2 J/g/K) (40°C − 0°C)

q = 4880 J

Heat lost by the steam:

q = mL + mCΔT

q = m (2200 J/g) + m (4.2 J/g/K) (100°C − 40°C)

q = 2452 J/g m

Plugging the values into the equation:

1920 J + 11760 J + 4880 J = 2452 J/g m

18560 J = 2452 J/g m

m = 7.6 g

7 0
2 years ago
When a car driving up a hill with constant speed: I. its kinetic energy is decreasing. II. its potential energy is constant. III
madam [21]

A car driving up a hill at a constant speed experiences no change in its kinetic energy while it's potential energy increases with increasing height, thus none of the options are correct.

Understanding the concept

Consider a car moving up the hill at a constant speed as shown in the figure below. The following forces act on the car:

  • N is the normal reaction force acting in an upward direction
  • f_s is the static friction force exerted due to friction between the road and the tires of the car
  • f_k is the rolling friction force in the direction opposing that of the  tire
  • mg is the force acting in a downward direction.
  • θ is the angle of inclination.

Here as the car is moving up the hill at a constant speed, the net force exerted on the car is zero. Also, the kinetic energy of the car will not change as its velocity is constant and the potential energy will change with increasing height. Thus, none of the given options are correct.

Learn more about motion on an incline here:

<u>brainly.com/question/13513083</u>

#SPJ4

5 0
1 year ago
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Doss [256]
They don't want to be killed or they are hiding
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In the question, you just gave a complete and detailed
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You might want to simplify the speed and make it a unit rate,
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