1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kherson [118]
3 years ago
9

At a temperature of 320K, the gas in a cylinder has a volume of 40.0 liters. If the volume of the gas is decreased to 20.0 liter

s, what must the temperature be for the gas pressure to remain constant?
A. 160 K
B. 273 K
C. 560 K
D. 140 K
Physics
2 answers:
Lerok [7]3 years ago
6 0
Assuming the gas behaves ideally,
PV/T = constant. P will also be constant in this giving us:
V₁/T₁ = V₂/T₂
40/320 = 20/T₂
T₂ = 160 K
The answer is A.
liraira [26]3 years ago
3 0

Answer:

The correct answer is option A.

Explanation:

Initial volume of the gas V_1= 40.0L

Initial temperature of gas T_1= 320 K

Final volume of the gas V_2= 20.0L

Final temperature of the gas = T_2

Applying Charles' Law:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

T_2=\frac{V_2\times T_1}{V_1}=\frac{20.0L\times 320 K}{40.0L}=160K

The temperature of the gas when volume of the gas is 20.0 L is 160 K.Hence, the correct answer is option A.

You might be interested in
Calculate the de Broglie wavelength of (a) a mass of 1.0 g traveling at 1.0 m s−1 , (b) the same, traveling at 1.00 × 105 km s−1
lesantik [10]

Answer:

a)\lambda=6.63\times10^{-31}m

b)\lambda=6.63\times10^{-39}m

c)\lambda=9.97\times10^{-11}m

d)\lambda=4.03\times10^{-36}m

e)λ=∞

Explanation:

De Broglie discovered that an electron or other mass particles can have a wavelength associated, and that wavelength (λ) is:

\lambda=\frac{h}{P}=\frac{h}{mv}

with h the Plank's constant (6.63\times10^{-34}\frac{m^{2}kg}{s}) and P the momentum of the object that is mass (m) times velocity (v).

a)\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}kg*1.0)}

\lambda=6.63\times10^{-31}m

b)\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}*(1.00\times10^{8}))}

\lambda=6.63\times10^{-39}m

c)\lambda=\frac{6.63\times10^{-34}}{(6.65\times10^{-27}*1000)}

\lambda=9.97\times10^{-11}m

d)\lambda=\frac{6.63\times10^{-34}}{(74*2.22)}

\lambda=4.03\times10^{-36}m

e) \lambda=\frac{6.63\times10^{-34}}{(74*0)}

λ=∞

6 0
3 years ago
Sort the forces as producing a torque of positive, negative, or zero magnitude about the rotational axis identified in part
Fantom [35]

a) Angular acceleration: 17.0 rad/s^2

b) Weight: conterclockwise torque, reaction force: zero torque

Explanation:

a)

In this problem, you are holding the pencil at its end: this means that the pencil will rotate about this point.

The only force producing a torque on the pencil is the weight of the pencil, of magnitude

W=mg

where m is the mass of the pencil and g the acceleration of gravity.

However, when the pencil is rotating around its end, only the component of the weight tangential to its circular trajectory will cause an angular acceleration. This component of the weight is:

W_p =mg sin \theta

where \theta is the angle of the rod with respect to the vertical.

The weight act at the center of mass of the pencil, which is located at the middle of the pencil. So the torque produced is

\tau = W_p \frac{L}{2}=mg\frac{L}{2} cos \theta

where L is the length of the pencil.

The relationship between torque and angular acceleration \alpha is

\tau = I \alpha (1)

where

I=\frac{1}{3}mL^2

is the moment of inertia of the pencil with respect to its end.

Substituting into (1) and solving for \alpha, we find:

\alpha = \frac{\tau}{I}=\frac{mg\frac{L}{2}sin \theta}{\frac{1}{3}mL^2}=\frac{3 g sin \theta}{2L}

And assuming that the length of the pencil is L = 15 cm = 0.15 m, the angular acceleration when \theta=10^{\circ} is

\alpha = \frac{3(9.8)(sin 10^{\circ})}{2(0.15)}=17.0 rad/s^2

b)

There are only two forces acting on the pencil here:

- The weight of the pencil, of magnitude mg

- The normal reaction of the hand on the pencil, R

The torque exerted by each force is given by

\tau = Fd

where F is the magnitude of the force and d the distance between the force and the pivot point.

For the weight, we saw in part a) that the torque is

\tau =mg\frac{L}{2} cos \theta

For the reaction force, the torque is zero: this is because the reaction force is applied exctly at the pivot point, so d = 0, and therefore the torque is zero.

Therefore:

- Weight: counterclockwise torque (I have assumed that the pencil is held at its right end)

- Reaction force: zero torque

8 0
3 years ago
which is these is a chemical change? 1. compressibility. 2. malleability. 3.color. 4. heat of combustion​
gulaghasi [49]
I think it’s color but not sure
4 0
2 years ago
A rigid tank contains 7 kg of an ideal gas at 5 atm and 30c. a valve is opened, and half of mass of the gas can escape. the fin
Readme [11.4K]
The equation of state for an ideal gas is
pV=nRT
where p is the gas pressure, V the volume, n the number of moles, R the gas constant and T the temperature.

The equation of state for the initial condition of the gas is
p_1 V_1 = n_1 R T_1 (1)
While the same equation for the final condition is
p_2 V_2 = n_2 R T_2 (2)

We know that in the final condition, half of the mass of the gas is escaped. This means that the final volume of the gas is half of the initial volume, and also that the final number of moles is half the initial number of moles, so we can write:
V_1 = 2 V_1
n_1 = 2 n_2
If we substitute these relationship inside (1), and we divide (1) by (2), we get
\frac{p_1}{p_2} = \frac{T_1}{T_2}

And since the initial temperature of the gas is T_1 = 30 C=303 K, we can find the final temperature of the gas:
T_2 = T_1  \frac{p_2}{p_1}=(303 K) \frac{1.5 atm}{5.0 atm}=90.9 K
6 0
3 years ago
Read 2 more answers
What is the purpose of life?
postnew [5]

Answer:

to live honorable

Explanation:

4 0
2 years ago
Other questions:
  • Complete the following table with the appropriate units of measurement. Word bank: gram, meter, kelvin, liter, second, grams/cm3
    10·2 answers
  • I need help like right now!!!!! please
    14·1 answer
  • When a wave passes from one medium to another, its _________ remains constant.
    9·1 answer
  • A 2.36 kg block resting on a frictionless surface is attached to an ideal spring with spring constant k = 260 Nm . A force is ap
    15·1 answer
  • A force causes a mass of 4 kg to have an acceleration of 8 m/s2. Suppose something causes the mass to be one-quarter of its orig
    14·1 answer
  • The melting of glaciers and the polar ice caps poses a devastating threat of potential flooding for low-lying areas. Scientists
    14·1 answer
  • 10 N pushes a 10 kg crate to the right. Determine the acceleration of the crate.
    11·1 answer
  • when you boil water to make pasta hot water from the bottom of the pan carries thermal energy to water molecules at the top the
    13·1 answer
  • Please help.................​
    9·2 answers
  • which of the answers below best describes the precaution you must make before connecting a capacitor to a circuit?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!