m = mass of the ice added = ?
M = mass of water = 1.90 kg
= specific heat of the water = 4186 J/(kg ⁰C)
= specific heat of the ice = 2000 J/(kg ⁰C)
= latent heat of fusion of ice to water = 3.35 x 10⁵ J/kg
= initial temperature of ice = 0 ⁰C
= initial temperature of water = 79 ⁰C
T = final equilibrium temperature = 8 ⁰C
using conservation of heat
Heat gained by ice = Heat lost by water
m (T - ) + m = M ( - T)
inserting the values
m (4186) (8 - 0) + m (3.35 x 10⁵ ) = (1.90) (4186) (79 - 8)
m = 1.53 kg
Ideal Gas Law PV = nRT
THE GASEOUS STATE
Pressure atm
Volume liters
n moles
R L atm mol^-1 K^-1
Temperature Kelvin
pv = rt
divide both sides by v
pv/v = rt/v
p = rt/v
answer: p = rt/v
Ideal Gas Law: Density
PV = NRT
PV = mass/(mw)RT
mass/V = P (MW)/RT = density
Molar Mass:
Ideal Gas Law PV = NRT
PV = mass/(MW) RT
MW = mass * RT/PV
Measures of Gases:
Daltons Law of Partial Pressures; is the total pressure of a mixture of gases equals the sum of the partial pressures of the individual gases.
Total = P_ A + P_ B
P_ A V = n_ A RT
P_ B V = n_ B R T
Partial Pressures in Gas Mixtures:
P_ total = P_ A + P_ B
P_ A = n_ A RT/V P_ B = n_ B RTV
P_ total = P_ A + P_ B = n_ total RT/V
For Ideal Gasses:
P_ A = n_ A RT/V P_ total = n_ toatal RT/V
P_ A/P_ total = n_ A RTV/n_ total RTV
= n_ A/n_ total = X_ A
Therefore, P_ A = X_ A P_ total.
PV = nRT
P pressure
V volume
n Number of moles
R Gas Constant
T temperture (Kelvin.).
Hope that helps!!!!!! Have a great day : )
Based on the options given, the most likely answer to this query is C) 4577 liters.
Upon computation of the given variables the result seems to be 4577 L
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Answer:
T = T
Explanation:
Time period of a simple pendulum is not affected by the mass of the bob. As we know, 
. There is no factor of mass affecting when we derived the equation. The basic reason behind the time period is not affected is because of mass dependence on angular acceleration. As the mass increases the acceleration increase and the Time Period remains constant.
