Answer:
B. 57.4 N horizontal (right)
<u>Explanation</u>:
using cos method:
<em>As its vertical, the direction of this force should be up.</em>
A bullet of .05 kg is fired into a block of wood. Knowing that the bullet left the gun with a muzzle velocity of 350. m/s, and t
1 answer:
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Answer:
Velocity.
Explanation:
Projectile motion is characterized as the motion that an object undergoes when it is thrown into the air and it is only exposed to acceleration due to gravity.
As per the question, 'any change in the initial velocity of the projectile(object having gravity as the only force) would lead to a change in the range as well as the maximum height of the projectile.' To illustrate numerically:
Horizontal range: As per expression:
R= (*sin2θ)/g
the range depending on the square of the initial velocity.
Maximum height: As per expression:
H= ( *
θ
)/2g
the maximum distance also depends upon square of the initial velocity.
Answer:
V=483.63 m/s
Explanation:
Given that
mass ,m= 5.31 x 10⁻²⁶ kg
Kinetic energy KE= 6.21 x 10⁻²¹ J
As we know that the kinetic energy of the mass m with moving velocity V given as
Now by putting the values
V=483.63 m/s
Therefore the velocity of the molecule at the room temperature will be 483.63 m/s.