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BARSIC [14]
3 years ago
11

A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length r. If I_1 is the m

oment of inertia of this object with respect to an axis passing through the center of the rod and perpendicular to it and l_2 is the moment of inertia with respect to an axis passing through one of the masses, it follows that l_1 = l_2. l_l > l_2. l_2 > l_1
Physics
1 answer:
Vanyuwa [196]3 years ago
7 0

Answer:I_2>I_1

Explanation:

Given

Shape of the object is dumbbell shaped

Moment of Inertia w.r.t an axis passing through center and perpendicular to it

I_1=m(\frac{r}{2})^2+m(\frac{r}{2})^2

I_1=\frac{mr^2}{2}

For the axis which passes through one of the masses

I_2=mr^2

so I_2>I_1

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Answer:

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Explanation:

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4 years ago
A student performs an activity to study how electric current flows in a circuit. The student constructs two different circuits,
natta225 [31]

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Explanation:

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3 years ago
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What is the voltage if the current is 4 A and the resistance is 10 Ω?
ZanzabumX [31]

Answer:

40 volts

Explanation:

Use the equation V=IR

V=(4)(10)

V=40

5 0
3 years ago
A student hears a police siren. What would change the frequency that the student hears? check all that apply
andriy [413]

Considering the Doppler efect, the frequency heard by the student would change if:

  • if the student walked toward the police car.
  • if the student walked away from the police car.
  • if the police car moved toward the student.
  • if the police car moved away from the student.

<h3>Doppler effect</h3>

The Doppler effect is defined as the change in the apparent frequency of a wave produced by the relative motion of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.

The following expression is considered the general case of the Doppler effect:

f'=f\frac{v+-vR}{v-+vE}

Where:

  • f', f: Frequency perceived by the receiver and frequency emitted by the transmitter, respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s⁻¹)
  • v: Wave propagation speed in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 343 m/s.
  • vR, vE: Receiver and transmitter speed respectively. Its unit of measure in the S.I. is the m/s
  • ±, ∓:
  • We will use the + sign:
  1. In the numerator if the receiver approaches the sender
  2. In the denominator if the sender moves away from the receiver
  • We will use the - sign:
  1. In the numerator if the receiver moves away from the sender
  2. In the denominator if the sender approaches the receiver

In summary, the Doppler Effect is an alteration of the observed frequency of a sound due to the movement of the source or the observer, that is, they are changes in the frequency and wavelength of a wave due to the relative movement between the wave source and the observer.

<h3>Changes on the frequency </h3>

In this case, considering the Doppler effect, the frequency heard by the student would change if:

  • if the student walked toward the police car.
  • if the student walked away from the police car.
  • if the police car moved toward the student.
  • if the police car moved away from the student.

Learn more about Doppler effect:

brainly.com/question/15307081

brainly.com/question/4052291

brainly.com/question/15097772

brainly.com/question/3841958

#SPJ12

7 0
2 years ago
A 4.55 nF parallel-plate capacitor contains 27.5 μJ of stored energy. By how many volts would you have to increase this potentia
aivan3 [116]

Answer:

\Delta V=V_{2}-V_{1}=45.4V

Explanation:

The energy, E, from a capacitor, with capacitance, C, and voltage V is:

E=\frac{1}{2} CV^{2}

V=\sqrt{2E/C}

If we increase the Voltage, the Energy increase also:

V_{1}=\sqrt{2E_{1}/C}

V_{2}=\sqrt{2E_{2}/C}

The voltage difference:

V_{2}-V_{1}=\sqrt{2E_{2}/C}-\sqrt{2E_{1}/C}

V_{2}-V_{1}=\sqrt{2*55*10^{-6}/4.55*10^{-9}}-\sqrt{2*27.5*10^{-6}/4.55*10{-9}}=45.4V

5 0
3 years ago
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