An 80.0 g sample of a gas was heated from 25 ∘C to 225 ∘C. During this process, 346 J of work was done by the system and its
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<u>Answer:</u> The mass of PVB required to produce 1000 grams of tape is 213.4 grams
<u>Explanation:</u>
To calculate the mass of aluminium oxide, we use the equation:
.......(1)
- <u>For
</u>
We are given:
50% (v/v) of
This means that 50 mL of aluminium oxide is present in 100 mL of tape
Calculating the mass of aluminium oxide by using equation 1:
Density of aluminium oxide =
Volume of aluminium oxide = (Conversion factor:
)
Putting values in equation 1, we get:
Mass of aluminium oxide = 199 g
- <u>For PVB:</u>
We are given:
50% (v/v) of PVB
This means that 50 mL of PVB is present in 100 mL of tape
Calculating the mass of PVB by using equation 1:
Density of PVB =
Volume of PVB =
Putting values in equation 1, we get:
Mass of PVB = 54 g
Mass of tape = Mass of aluminium oxide + mass of PVB
Mass of tape = [199 + 54] g = 253 g
To calculate the mass of PVB required to produce 1000 g of tape, we use unitary method:
When 253 grams of tape is made, the mass of PVB required is 54 g
So, when 1000 grams of tape is made, the mass of PVB required will be =
Hence, the mass of PVB required to produce 1000 grams of tape is 213.4 grams
Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.
Explanation:
Given: = 61 L,
= 183 K,
= 0.60 atm
At STP, the value of pressure is 1 atm and temperature is 273.15 K.
Now, formula used to calculate the new volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.