Answer:
100 grams of C-14 decays to 25 grams in 11,460 years.
The C-14 isotope is only useful for dating fossils up to about 50,000 years old
If an ancient bone contains 6.25% of its original carbon, then the bone must be 22,920 years old.
Explanation:
We already know that the half life of C-14 is 5,730 years. After the first half life, we have 50 grams remaining. This takes 5,730 years. After the second half life (11,460 years now gone) we have 25 grams of C-14 left.
If a fossil material is older than 50,000 years an undetectable amount of 14C is left in the sample hence Carbon-14 is no longer suitable for dating the sample.
From;
0.693/5730 = 2.303/t log (No/0.0625No)
Where;
t = time taken and No = initial amount of C-14
0.693/5730= 2.77/t
t = 22,920 years
Answer:
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Explanation:
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Explanation:
- area of rectangle=l×b
2.area of rectangle=l×b
3. perimeter of square=4×L
4. perimeter of rectangle=2(L+b)
- 14=2(4+b)
- 14=8+2b
- 2b=6
- b=3cm
hope it helps.
Answer: The answer is C
Explanation: Sound waves tend to spread farther the deeper the sound is, and the waves go lower then the second example, deeming it is louder.
The ratio of buffer C₂H₃O₂ /HC₂H₃O₂ must you use are1:0.199 or 10:2
the ratio of buffer C₂H₃O₂ /HC₂H₃O₂ can be calculate using the Henderson-Hasselbalch Equation which relates the pH to the measure of acidity pKa. The equation is given as:
pH = pKa + log ([base]/[acid]
Where,
[base] = concentration of C₂H₃O₂in molarity or moles
[acid] = concentration of HC₂H₃O₂ in molarity or moles
For the sake of easy calculation, allow us to assume that:
[base] =1
[acid] = x
Therefore using equation 1,
5.44 = 4.74 + log (1 / x)
log [base / acid] = 0.7
1 / x = 5.0118
x = 0.199
The required ratio of buffer C₂H₃O₂ /HC₂H₃O₂ is 1:0.199 or 10:2
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