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Marta_Voda [28]
1 year ago
9

you wish to prepare an hc2h3o2 buffer with a ph of 5.44. if the pka of the acid is 4.74, what ratio of c2h3o2-/hc2h3o2 must you

use?
Chemistry
1 answer:
vazorg [7]1 year ago
5 0

The ratio of buffer C₂H₃O₂ /HC₂H₃O₂  must you use are1:0.199 or 10:2

the ratio of buffer C₂H₃O₂ /HC₂H₃O₂  can be calculate using the Henderson-Hasselbalch Equation which relates the pH to the measure of acidity pKa. The equation is given as:

pH = pKa + log ([base]/[acid]

Where,

[base] = concentration of C₂H₃O₂in molarity or moles

[acid] = concentration of HC₂H₃O₂ in molarity or moles

For the sake of easy calculation, allow us to assume that:

[base] =1

[acid] = x

Therefore using equation 1,

5.44 = 4.74 + log (1 / x)

log [base / acid] = 0.7

1 / x = 5.0118

x = 0.199

The required ratio of buffer C₂H₃O₂ /HC₂H₃O₂ is 1:0.199 or 10:2

learn more about buffer ratio here brainly.com/question/4342532

#SPJ4

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Answer:

D. N₂O

Explanation:

Let's assume we have 100 g of the compound.  That means it consists of 63.61 grams of nitrogen and 36.69 grams of oxygen.

Converting masses to moles:

63.61 g N × (1 mol N / 14.01 g N) = 4.540 mol N

36.69 g O × (1 mol O / 16.00 g O) = 2.293 mol O

Normalize by dividing by the smallest:

4.540 / 2.293 = 1.980 mol N

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3 years ago
What volume of 1.60 M hydrochloric acid solution (HCI) is required to neutralize 48.0 mL of 0.200 M sodium
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Answer:

Volume of HCl require =  6 mL

Explanation:

Given data:

Volume of HCl require = ?

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Volume of NaOH = 48.0 mL

Molarity of NaOH = 0.200 M

Solution:

Formula:

M₁V₁     =      M₂V₂

By putting values,

1.60 M×V₁  =  0.200 M×48.0 mL

V₁  =  0.200 M×48.0 mL/1.60 M

V₁  =  9.6 M .mL /1.60 M

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A 5.00-g sample of copper metal at 25.0 °C is heated by the addition of 133 J of energy. The final temperature of the copper is
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<u>Answer:</u> The final temperature of the copper is 95°C.

<u>Explanation:</u>

To calculate the final temperature for the given amount of heat absorbed, we use the equation:

Q= m\times c\times \Delta T

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\Delta T={\text{Change in temperature}}=T_2-T_1

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Putting values in above equation, we get:

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Hence, the final temperature of the copper is 95°C.

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