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3 years ago

W1 has a weight of 220 N acting 0.6m away from the pivot.

Physics

1 answer:

Leya [2.2K]3 years ago

3 0

Answer:

0.73m

Explanation:

Given parameters:

W1 = 220N

D1 = 0.6m

W2 = 180N

Unknown

D2 = ?

Solution:

The torque on each side must be balanced;

Torque = force x distance

T₁ = T₂

W1 x D1 = W2 x D2

Insert the parameters and solve for D2;

220 x 0.6 = 180 x D2

132 = 180D2

D2 = $\frac{132}{180}$ = 0.73m

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Answer:

Explanation:

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t₁= 16.7 years

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t₁= 10.9 years

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$\frac{20}{\sqrt{1-\frac{.64c^2}{c^2} } }$

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3 years ago

A tire has a pressure of 325 kPa at 10°C.

musickatia [10]

5 times that of initial pressure i.e 1625 kpa

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3 years ago

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The velocity vector of an object with a centripetal acceleration is never tangent to the circular path.

Veseljchak [2.6K]

The velocity vector of an object with a centripetal acceleration is never tangent to the circular path is False.

Answer: False

Explanation:

Centripetal acceleration is a feature of objects in uniform circular motion. In that case velocity is along the tangent drawn to the circular path. For an object to be called accelerating its velocity should be variable but speed needn’t.

Even when the speed is constant an object can be accelerating. The direction of velocity of an object in uniform circular motion keeps changing continuously. This change in velocity in uniform circular motion is equal to the centripetal acceleration.

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3 years ago

A 62.0 kg water skier at rest jumps from the dock into a 775 kg boat at rest on the east side of the dock. If the velocity of th

Dominik [7]

Answer:

v = 0.33 m/s

Explanation:

The final velocity of the skier and boat can be calculated by conservation of the lineal momentum:

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