What is the value of (-3) to the power of negative two

Anne is taping 7 boxes for storage. She uses feet of tape to close each box. How much tape will Anne need to tape the boxes? Exp

aleksandrvk [35]

D is the correct answer

hope this helps

7 0

3 years ago

In the diagram, the measure of angle 6 is 98°. what is the measure of angle 7?

lesya [120]

Answer:

7∠82°

Step-by-step explanation:

Well angle 6 and 7 are complementary angles, meaning they both add up to 180°.

So we do 180 - 98 which is 82°.

4 0

3 years ago

Read 2 more answers

Match the number with its opposite. (4 points)

bazaltina [42]

I hope this helps!!!

1.C
2.A
3.B
4.D

8 0

3 years ago

Lines g, h, and I are parallel and m < 2 =129

vampirchik [111]

Answer:

All angles in this diagram are 51 or 129. See below for a specific angle.

Step-by-step explanation:

Parallel lines cut by a transversal have specific angle relationships.

Alternate Interior Angles are angles across the transversal between pairs of parallel lines. These angles are congruent. Example: 3, 6, 7, and 10 are all congruent and are pairs of alternate interior angles. 4, 5, 8, and 9 are congruent as well.
Alternate Exterior Angles are angles across the transversal outside of the parallel lines. These angles are congruent. Example 2 & 11 are congruent alternate exterior angles. 1 and 12 are another set.
Supplementary angles are angles which form a line and add to 180. If angle 1 + angle 2 = 180 and angle 2 = 129, then Angle 1+ 129 =180. Angle 1 must be 51 degrees.
Vertical angles are angles across a vertex. They are congruent. Example: Angle 2 and Angle 3 are both 129.

Using these relationships, the following angles have the following measures:

Angle 1 = 51

Angle 2 = 129

Angle 3 = 129

Angle 4 = 51

Angle 5 =51

Angle 6 = 129

Angle 7 = 129

Angle 8 = 51

Angle 9 = 51

Angle 10 = 129

Angle 11 = 129

Angle 12 = 51

3 0

3 years ago

Will Mark Brainiest!!! Simplify the following:

xz_007 [3.2K]

Answer:

1.B

2.A

3. B

Step-by-step explanation:

1. $\frac{x+5}{x^{2} + 6x +5 }$

We have the denominator of the fraction as following:

$x^{2} + 6x + 5 \\= x^{2} + (1 + 5)x + 5\\= x*x + 1x + 5x + 5*1\\= x ( x + 1) + 5(x + 1)\\= (x + 1) (x + 5)$

As the initial one is a fraction, so that its denominator has to be different from 0.

=> ( $x^{2} +6x+5$ ) ≠ 0

⇔ (x +1) (x +5) ≠ 0

⇔ (x + 1) ≠ 0; (x +5) ≠ 0

⇔ x ≠ -1; x ≠ -5

Replace it into the initial equation, we have:

$\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)}$

As (x+5) ≠ 0; we divide both numerator and denominator of the fraction by (x +5)

=> $\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)} = \frac{1}{x+1}$

So that $\frac{x+5}{x^{2} + 6x +5 } = \frac{1}{x+1}$ with x ≠ 1; x ≠ -5

So that the answer is B.

2. $\frac{(\frac{x^{2} -16 }{x-1} )}{x+4}$

As the initial one is a fraction, so that its denominator has to be different from 0

=> x + 4 ≠ 0

=> x ≠ -4

As $\frac{x^{2}-16 }{x-1}$ is also a fraction, so that its denominator (x-1) has to be different from 0

=> x - 1 ≠ 0

=> x ≠ 1

We have an equation: $x^{2} - y^{2} = (x - y ) (x+y)$

=> $x^{2} - 16 = x^{2} - 4^{2} = (x -4) (x +4)$

Replace it into the initial equation, we have:

$\frac{(\frac{x^{2} -16 }{x-1} )}{x+4} \\= \frac{x^{2} -16 }{x-1} . \frac{1}{x + 4}\\= \frac{(x-4)(x+4)}{x-1}. \frac{1}{x + 4}$

As (x + 4) ≠ 0 (proven above), we can divide both numerator and the denominator of the fraction by (x +4)

=> $\frac{(x-4)(x+4)}{x-1} .\frac{1}{x+4} =\frac{x-4}{x-1}$

So that the initial equation is equal to $\frac{x-4}{x-1}$ with x ≠-4; x ≠1

=> So that the correct answer is A

3. $\frac{x}{4x + x^{2} }$

As the initial one is a fraction, so that its denominator (4x + x^2) has to be different from 0

We have:

(4x + x^2) = 4x + x.x = x ( x + 4)

So that: (4x + x^2) ≠ 0 ⇔ x ( x + 4 ) ≠ 0

⇔ $\left \{ {{x\neq 0} \atop {(x+4)\neq0 }} \right.$ ⇔ $\left \{ {{x\neq 0} \atop {x \neq -4 }} \right.$

As (4x + x^2) = x ( x + 4) , we replace this into the initial fraction and have:

$\frac{x}{4x + x^{2} } = \frac{x}{x(x+4)}$

As x ≠ 0, we can divide both numerator and denominator of the fraction by x and have:

$\frac{x}{x(x+4)} =\frac{x/x}{x(x+4)/x} = \frac{1}{x+4}$

So that $\frac{x}{4x+x^{2} } = \frac{1}{x+4}$ with x ≠ 0; x ≠ -4

=> The correct answer is B

3 0

3 years ago