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2 years ago

Which is least likely to occur after an experiment i conducted to test a hypothesis?

Chemistry

1 answer:

Alenkinab [10]2 years ago

8 0

Answer:

The hypothesis becomes a theory if the results support it is answer.

Explanation:

I hope it's helpful!

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Ka/KbMIXED PRACTICE108.Calculate the [H3O+(aq)], the pH, and the % reaction for a 0.50 mol/L HCN solution. ([H3O+(aq)] = 1.8 x 1

NeTakaya

Answer:

a) [H₃O⁺] = 1.8x10⁻⁵ M

b) pH = 4.75

c) % rxn = 3.5x10⁻³ %

Explanation:

a) The dissociation reaction of HCN is:

HCN(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CN⁻(aq)

0.5 M - x x x

The dissociation constant from the above reactions is given by:

$Ka = \frac{[H_{3}O^{+}][CN^{-}]}{[HCN]} = 6.17 \cdot 10^{-10}$

$6.17 \cdot 10^{-10} = \frac{x*x}{(0.5 - x)}$

$6.17 \cdot 10^{-10}*(0.5 - x) - x^{2} = 0$

By solving the above quadratic equation we have:

x = 1.75x10⁻⁵ M = 1.8x10⁻⁵ M = [H₃O⁺] = [CN⁻]

Hence, the [H₃O⁺] is 1.8x10⁻⁵ M.

b) The pH is equal to:

$pH = -log[H_{3}O^{+}] = -log(1.75 \cdot 10^{-5} M) = 4.75$

Then, the pH of the HCN solution is 4.75.

c) The % reaction is the % ionization:

$\% = \frac{x}{[HCN]} \times 100$

$\% = \frac{1.75 \cdot 10^{-5} M}{0.5 M} \times 100$

$\% = 3.5 \cdot 10^{-3} \%$

Therefore, the % reaction or % ionization is 3.5x10⁻³ %.

I hope it helps you!

6 0

2 years ago

_P4 + ____O2 → __P2O3<br><br> How do I balance this equation?

Murljashka [212]

Explanation:

please mark me as brainlest

5 0

2 years ago

Read 2 more answers

Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these were decomposed the sulfur dioxide produce

Zinaida [17]

Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

Explanation : Given,

Mass of oxygen in sulfur dioxide = 3.49 g

Mass of sulfur in sulfur dioxide = 3.50 g

Mass of oxygen in sulfur trioxide = 9.00 g

Mass of sulfur in sulfur trioxide = 6.00 g

Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.

Mass of oxygen per gram of sulfur for sulfur dioxide = $\frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}$

Mass of oxygen per gram of sulfur for sulfur dioxide = $\frac{3.49}{3.50}=0.997g$

and,

Mass of oxygen per gram of sulfur for sulfur trioxide = $\frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}$

Mass of oxygen per gram of sulfur for sulfur trioxide = $\frac{9.00}{6.00}=1.5g$

Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

8 0

3 years ago

Calculate the volume in milliliters of a 1.27 mol/L silver perchlorate solution that contains 125.mmol of silver perchlorate (Ag

Lunna [17]

Answer:

This solution has a volume of 98.4 mL

Explanation:

Step 1: Data given

Molarity of AgClO4 solution = 1.27 mol/L

Number of moles AgClO4 = 125 mmol = 0.125 mol

Molar mass of AgClO4= 207.32 g/mol

Step 2: Calculate volume of the 1.27 M solution

Molarity = moles / volume

Volume = moles / molarity

Volume = 0.125 moles / 1.27 mol /L

Volume = 0.0984 L = 98.4 mL

This solution has a volume of 98.4 mL

7 0

3 years ago

According to the activity series, which one of the following reactions will occur?

Korvikt [17]

Answer:

i think

SrF2 + Br2 --->

dont count me on it

Explanation:

balanced

3 0

2 years ago