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Nikolay [14]
3 years ago
5

Select the TRUE statements below regarding the coordination compound prepared in lab. Group of answer choices The coordination c

ompound contained a complex ion that was covalently bonded to sulfate. The ligand must have at least one unshared pair of valence electrons in order to covalently bond with transition metal in the coordination compound. Ethanol was used during crystallization of the coordination compound because the compound is soluble in ethanol. The ammonia is covalently bonded to the transition metal. The colors of many coordination compounds are the result of light absorption by the d electrons on the transition metal.
Chemistry
1 answer:
Vanyuwa [196]3 years ago
7 0

Answer: Hello the compound is missing but I was able to get the Full question and missing compound . ( compound = copper sulfate )

<em>answer</em> : statement ; 2 , 3 and 5

Explanation:

The true statements regarding the coordination compound ( copper sulfate ) are :

  • The ligand must have at least one unshared pair of valence electrons in order to covalently bond with transition metal in the coordination compound ( statement 2 )
  • Ethanol was used during crystallization of the coordination compound because the compound is soluble in ethanol ( statement 3 )
  • The colors of many coordination compounds are the result of light absorption by the d electrons on the transition metal ( statement 5 )

During the coordination of compounds dative bonds exits between the transition metals and the Ligands molecules

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aqueous lithium hydroxide solution is used to purify air (remove co2) in spacecrafts and submarines. the pressure of carbon diox
oksano4ka [1.4K]

The mass of the water is 1580 g.

<h3>What is the amount of water formed?</h3>

We know that the ideal gas equation can be used to obtain the number of moles of the gas. We have been told that the pressure of the gas reduced from  7.9 x 10-3 atm to  1.2 x 10-4 atm. The change in pressure can be used obtain the number of moles.

Change in pressure = 7.9 x 10-3 - 1.2 x 10-4 = 7.78 * 10^-3 atm

Using;

PV = nRT

n = PV/RT

n = 7.78 * 10^-3 atm *  2.4 x10^5 l/0.082 * (39 + 273)

n = 85 moles

Since 1 mole of carbon dioxide produces 1 mole of water

85 moles of carbon dioxide produces 85 mole of water

Mass of water produced = 85 mole  * 18 g/mol

= 1580 g

Learn more about ideal gas equation:brainly.com/question/4147359

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6 0
1 year ago
Select the correct answer.
vichka [17]

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Other important considerations are

local environment: plants and animals that could be affected by the system; community support and buy-in.wind, hail, rain, snow profile for the location in question. if there are high/tropical winds then it will increase the plant cost.flight paths and roads near the plant which could be affected by glint and glareproximity to a local town where staff will be able to live both during construction and later during operationproximity to a electricity transmission line with available capacityavailability of water for mirror cleaning and steam blowdown.cost (and availability) of electricity in the area. If remote, electricity/energy may be very expensive, which will enable a high price for electricity sold from the plant.quality of road to the plant, required to bring equipment and materials to sitepolitical stability of the region -- potential impact on perceived bankability of the project.

Many of these items will have a large influence on the cost of the plant and/or the revenue it will generate during its life. Others relate to environmental and risk factors and are also critically important to consider.

Hope this helps!!

6 0
1 year ago
6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/
Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}

(b) Percent transmission

A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}

7) Absorbance

A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}

8 0
3 years ago
A gas occupies 4.00 L at 2.00 atm pressure. At what pressure would the volume be 6.00 L if the temperature remains constant?
kherson [118]
P1V1= P2V2 
P1= 2
V1=4
V2=6
answere= (8/6)
8 0
3 years ago
Read 2 more answers
How many atoms below?
zlopas [31]

Answer:

44

Explanation:

6 0
3 years ago
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