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2 years ago

How many atoms of gold (Au) are equal to 212g of gold?

Chemistry

1 answer:

Lostsunrise [7]2 years ago

8 0

Given :

Mass of gold ( Au ) is 212 gram.

To Find :

Atoms of gold present in 212 gram of gold.

Solution :

Molecular mass of gold is 197 gram.

So, number of moles of gold in 212 gram is :

$n = \dfrac{212}{197} \ moles\\\\n = 1.076 \ moles$

Now, we know 1 mole of any element contains $6.022 \times 10^{23}$ atoms.

So, number of atoms present in 1.076 moles are :

$N = 1.076 \times 6.022\times 10^{23}\\\\N = 6.48 \times 10^{23}$

Hence, this is the required solution.

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What is the molar mass of Sn(CO3)2?

Free_Kalibri [48]

Answer:

The molar mass and molecular weight of Sn(CO3)2 is 238.728.

Explanation:

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2 years ago

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AleksandrR [38]

Answer:

Supersaturated

Explanation:

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2 years ago

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What is a real life example of Charles’ law?

max2010maxim [7]

Leaving a basketball out in the cold weather. When a basketball if left in a cold garage or outside during the cold months, it loses its air inside (or volume).

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3 years ago

Which element has a larger atomic radius than sulfur? chlorine cadmium fluorine oxygen

zhuklara [117]

Answer:

Cadmium has larger atomic radius than sulfur.

Explanation:

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

Oxygen and fluorine are in the period 3, being oxygen to the left of fluorine, so oxygen is larger than fluorine.

Sulfur and chlorine are in the period 4, being sulfur to the left of chlorine, so sulfur is larger than chlorine.

Now see whan happens down a group. Atomic radius increases from top to bottom within a group due to electron shielding. That permits you to compare the size of the elements in a group:

Fluorine and chlorine are in the same group (17), with chlorine directly below fluorine, so the atomic radius of chlorine is larger than the atomic radius of fluorine.

Sulfur and oxygen are in the same group (16), with sulfur directlly below oxygen, so sulfur the atomic radius of sulfur is larger than the atocmi radius of oxygen.

So far, you can rank the atomic radius of sulfur, chlorine, fluorine, and oxygen, in increasing order as:

O < F < Cl < S, concluding that O, F, and Cl have smaller atomic radius than S.

Cadmiun, Cd, is to the left and below sulfur, so both electron shielding (down a group) and increase of the number of protons (down a period) lead to predict the cadmium has a larger atomic radius than sulfur.

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2 years ago

Balance the following oxidation-reduction reactions, which take place in acidic solution, by using the "half-reaction" method.

LuckyWell [14K]

First identify which is being oxidized and reduced. In this case, the Mg is being oxidized and the Hg is being reduced.

Mg --> Mg+2

Hg+2 --> Hg+1

Then you have to balance each half reaction first with electrons before adding them together in one equation

$Mg$ ⇒ $Mg^{+2} + 2e^{-1}$

and

$2Hg^{+2} + 2e^{-1}$ ⇒ $Hg_{2} ^{+2}$

and then combine them together to form

$Mg + 2 Hg^{+2} + 2e$ ⇒ $Mg^{+2} + 2e ^{-} + 2 Hg^{+1} + 2 e^{-}$

It isn't necessary to keep the electrons but its essential to know how many there are in order to know how many are in the equation in order to calculate the reaction energy. Note: Add H+ and H2O to balance the H's and O's in acidic solution if needed.

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3 years ago