What is the correct formula

An aluminum block has a density of 2.70 g/mL. If the mass of the block is 24.60 g, find the volume of the substance.

harina [27]

Volume of a substance can be determined by dividing mass of the substance by its density.

That can be mathematical shown as:

Density=Mass/Volume

So, Volume=Mass/Density

Here mass of the substance given as 24.60 g

Whereas density of the substance is 2.70 g/mL

So,

Volume=Mass/Density

=24.6/2.7

=9.1 mL

So volume of the substance is 9.1 mL.

8 0

3 years ago

The rate of effusion of a particular gas was measured and found to be 24.0 mL/min. Under the same conditions, the rate of effusi

Norma-Jean [14]

Answer:

63.6g/mol

Explanation:

Use the equation of effusion:

47.8/24= $\sqrt{x/16.04}$

solve for x you get 63.6g/mol

3 0

3 years ago

Name each of the following molecular binary compounds:

Tanya [424]

Answer:

Explanation:

From the given information; we are to assign the correct naming for the molecular binary compounds.

01. CaCl2 → Calcium CHloride

02. HI (g) → Hydrogen mono iodide gas

03. HI (aq) → Hydroiodic acid

04. BH3 → Borontrihydride

05. Cl2O6 → Dichlorine hexoxide

06. ClF → Chlorine monoflouride

07. P2Cl4 → Phosphorus tetrachloride

08. I2O5 → Diiodine pentaoxide

09. BrF5 → Bromine pentaflouride

10. HBr(aq) → Hydrobromic acid

11. IF7 → Iodine heptaflouride

12. NF3 → nitrogen triflouride

13. H2Se(aq) → hydroselenic acid

14. BrCl → Bromine monochloride

15. H2Se(g) → Hydrogen Selenide

16. SnO2 → Tindeoxide

17. HBr(g) → Hydrogenbromide gas

18. AsF3 → Arsenic triflouride

19. N2O3 → Dinitrogentrioxide

20. IF4 → Iodine pentafluoride

01. hydroiodic acid → HI (aq)

02. hydrogen monoiodide gas → HI (g)

03. diiodine tetraoxide → I2O4

04. bromine monofluoride → BrF

05. silicon tetrahydride → SiH4

06. tetraphosphorus hexaoxide → P4O6

07. disulfur monoxide → S2O

08. carbon monooxide → CO

09. hydrogen monochloride gas → Hcl

10. tetraphosphorus decaoxide → P4O10

11. dibromine monoxide → Br2O

12. dinitrogen tetrafluoride → N2F4

13. disilicon hexahydride → SiH6

14. tetraarsenic hexaoxide → As4O6

15. hydrochloric acid → HCl (aq)

16. arsenic trihydride → AsH3

17. iodine heptafluoride → IF7

18. bromine dioxide → BrO2

19. disulfur decafluoride → S2F10

20. dichlorine heptaoxide → Cl2O7

4 0

3 years ago

In this experiment, we will be performing a titration with a buret. place the steps in order. 1. record the ph when 0.0 ml of na

77julia77 [94]

I am guessing that your solutions of HCl and of NaOH have approximately the same concentrations. Then the equivalence point will occur at pH 7 near 25 mL NaOH.

The steps are already in the correct order.

1. Record the pH when you have added 0 mL of NaOH to your beaker containing 25 mL of HCl and 25 mL of deionized water.

2. Record the pH of your partially neutralized HCl solution when you have added 5.00 mL of NaOH from the buret.

3. Record the pH of your partially neutralized HCl solution when you have added 10.00 mL, 15.00 mL and 20.00 mL of NaOH.

4. Record the NaOH of your partially neutralized HCl solution when you have added 21.00 mL, 22.00 mL, 23.00 mL and 24.00 mL of NaOH.

5. Add NaOH one drop at a time until you reach a pH of 7.00, then record the volume of NaOH added from the buret ( at about 25 mL).

6. Record the pH of your basic HCl-NaOH solution when you have added 26.00 mL, 27.00 mL, 28.00 mL, 29.00 mL and 30.00 mL of NaOH.

7. Record the pH of your basic HCl-NaOH solution when you have added 35.00 mL, 40.00 mL, 45.00 mL and 50.00 mL of NaOH from your 50mL buret.

4 0

3 years ago

An equilibrium mixture contains 0.750 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the

sasho [114]

1.302 moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

$\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}$