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3 years ago

If the temperature changes in a chemical reaction, what has occurred?

Chemistry

1 answer:

bazaltina [42]3 years ago

3 0

Answer:

Energy was transferred

Explanation:

If the temperature changed, energy must have been added or lost, but not created. Energy can't be created or destroyed.

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How are scientific methods used?

dalvyx [7]

Scientific methods are used to study living things or investigate questions and solve problems.

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4 years ago

WILL MARK BRAINLIEST!!<br><br> Need help plsss

zlopas [31]

6.32 KJ is how much heat is given off

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3 years ago

A student creates a solution by dissolving some Na2SO4 (molar mass = 142.05 g/mol) in enough water to create 0.500 L of solution

NeX [460]

Answer : The mass of $Na_2SO_4$ is, 4.43 grams.

Explanation :

As we know that, when $Na_2SO_4$ dissolve in water then it dissociates to give 2 mole of sodium ion $Na^+$ and 1 mole of sulfate ion $SO_4^{2-}$

The chemical reaction will be:

$Na_2SO_4\rightarrow 2Na^++SO_4^{2-}$

Thus, the concentration of $Na_2SO_4$ = $\frac{\text{Concentration of }Na^+}{2}=\frac{0.125M}{2}=0.0625M$

First we have to calculate the moles of $Na_2SO_4$

$\text{Concentration of }Na_2SO_4=\frac{\text{Moles of }Na_2SO_4}{\text{Volume of solution}}$

$0.0625M=\frac{\text{Moles of }Na_2SO_4}{0.500L}$

$\text{Moles of }Na_2SO_4=0.0312mol$

Now we have to calculate the mass of $Na_2SO_4$

$\text{Mass of }Na_2SO_4=\text{Moles of }Na_2SO_4\times \text{Molar mass of }Na_2SO_4$

Molar mass of $Na_2SO_4$ = 142 g/mol

$\text{Mass of }Na_2SO_4=0.0312mol\times 142g/mol=4.43g$

Thus, the mass of $Na_2SO_4$ is, 4.43 grams.

6 0

3 years ago

What do YOU think? Is the movement to 100% renewable energy possible? Why, or why not?

NARA [144]

Answer:

i dont know

Explanation:

ask your science teacher

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3 years ago

Part D

qwelly [4]

Answer:

Explanation:

The number on the top right of the symbol shows ATOMIC NUMBER , if it is written alone only one digit or number overall .

And if the number is also in bottom left then bottom left number will be ATOMIC NUMBER and top right will be MASS NUMBER

Hope this will help you *-*

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3 years ago