Explanation:
Plants, as a autotrophs have chlorophyll to capture light energy from sun to make starch and sugar. Then, consumers eat plants, and the sugar is transferred to higher trophic level in a form of organic food. Nevertheless, energy is lost by uneaten food, indigestible food, unabsorbed food, excretory waste (eg co2) and heat loss by respiration.
<span>The correct answer is: Oxygen
Explanation:
In order to function properly (movement etc.) during exercise, muscles require oxygen. During exercise, the depth as well as the rate of breathing increase, which in turn increases the amount of oxygen inhaled. In order to expand and contract lungs and for other bodily movements, muscles require oxygen, and for that, more oxygen is carried in the blood to muscles. Hence, the correct answer is Oxygen.</span>
Answer:
The gravitational potential energy the barbells have at the maximum height, is P.E. = 3680·h J = 1.10 × 10⁴ units
Where;
h = The maximum height to which he lifts the barbells
Explanation:
The given parameters are;
The amount of work done by the championship lifter in lifting the weight, W = 1.10 × 10⁴ units
The weight of the barbells lifted by the championship lifter, N = 3680 N
The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;
P.E. = m × g × h
Where;
m = The mass of the barbells;
g = The acceleration due to gravity = 9.8 m/s²
h = The maximum height to which the barbells are lifted by the championship weight lifter
m × g = The weight of the barbells = 3680 N
∴ P.E. = 3680 N × h = 3680·h J
By the conservation of energy principle, work done by the championship weight lifter = The maximum gravitational potential energy gained by the barbell = The gravitational potential energy at the maximum height, P.E.
∴ The gravitational potential energy the barbells have at the maximum height, P.E. = 3680·h J = W = 1.10 × 10⁴ units
The electric potential difference (which is also the voltage) is calculated as the magnitude of the electric field multiplied by the distance moved. For this problem, we have (200 N/C) for the electric field multiplied by 5.0 cm. We first convert 5.0 cm to 0.05 m, then multiply by 200 N/C to get 10 N-m/C = 10 J/C = 10 V.
The work itself is obtained by multiplying the potential difference by the charge of an electron (which is 1.602 x 10^-19 C). So multiplying 10 V by 1.602 x 10^-19 C, we get 1.602 x 10^-18 V-C, which is 1.602 x 10^-18 J. Rounding off to one decimal place, this is 1.6 x 10^-18 J.
