Answer:
The convection coefficient is 
Solution:
Mass flow rate, 
Inner diameter of the tube, d = 0.014 m
Fluid density, 
Specific Heat, C = 3845 J/K
Thermal Conductivity, K = 0.74
Prandtl Number, 
Heat flux, 
Viscosity, 
Now,
To calculate the convection heat coefficient, h:
Determine the cross sectional area of the circular tube:
Determine the velocity of the fluid inside the tube by mass flow rate:


v = 2.624 m/s
Determine the Reynold's Number,
:


Thus it is clear that
> 10,000 hence flow is turbulent.
Now,
Determine the Nusselt Number:


Also,

where
h = convection coefficient
Now,

