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4 years ago

6

Do you think that rubbing two pieces of woods together would have more or less friction than wood rubbing against smooth metal ?

why?

1 answer:

salantis [7]4 years ago

7 0

Answer: More friction

Explanation: The wood would probably splinter, causing even more friction, while the metal would probably smooth the wood out.

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Find the moment of inertia of a hoop (a thin-walled, hollow ring) with mass m and radius r about an axis perpendicular to the ho

Gala2k [10]

By parallel axis theorem, mr^2 + mr^2 = 2mr^2

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3 years ago

Sunlight is made up of EM waves. True or False

GrogVix [38]

Answer:

true

Explanation:

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3 years ago

Although the use of absorbances at 450 nm provided you with maximum sensitivity, the absorbances at, say, 400 nm or 500 nm are n

AleksAgata [21]

Answer:

Yes, the value will be the same.

Explanation:

Yes, or at least to some degree, that value of K will remain the same. You're looking for a difference in absorbance, and the difference should be visible at all wavelengths, not only at the limit. That being said, resolution varies, and if we don't read the value to the maximum, we can get a less accurate reading.

4 0

3 years ago

Precautions taken when doing experiment on simple pendulum

olchik [2.2K]

Answer:

1.)The bob of pendulum should be displaced with a small angle.

2) The amplitude of the oscillation of a simple pendulum should be small.

3) Fans should be switched off to reduce the air resistance.

4)The simple pendulum should be oscillate in a vertical plane

Hope this helped you

7 0

3 years ago

4720 kj of energy are supplied to a material in order to raise its temperature by 65k. if the specific heat capacity of the mate

jeka57 [31]

The mass of material is 26.6 Kg

Given:

Q = 4720 KJ

Change in Temperature (AT) = 65 K

Specific heat capacity of material (c) = 2730 J K Kg*K

The relation between Q, AT, c and m are related by following formula: Q=m* c*∆T,

Plugging value in heat formula:

4720KJ = m* 2730 J/Kg*K * 65K

4720KJ = m * 177450J/kg

Converting 177450 J/kg to Kg/KJ

177450 J/kg*1KJ/1000J = 177.450KJ/kg

Dividing both side by 177.450KJ/kg

4720KJ/177.450KJ/Kg = m*177.450KJ/Kg÷ 177.450KJ/Kg

Hence, the mass of material = 26.6 Kg

Learn more about Mass here:

brainly.com/question/19385703

#SPJ4

6 0

2 years ago