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cricket20 [7]
3 years ago
6

Do you think that rubbing two pieces of woods together would have more or less friction than wood rubbing against smooth metal ?

why?
Physics
1 answer:
salantis [7]3 years ago
7 0

Answer: More friction

Explanation: The wood would probably splinter, causing even more friction, while the metal would probably smooth the wood out.

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What are two most important processes in the cycling of oxygen in and out of the atmosphere?
natulia [17]
Weathering and erosion
7 0
3 years ago
A total charge of 4.70 is distributed on two metal spheres. When the spheres are 10 cm apart, they each feel a repulsive force o
Anna35 [415]

Answer:0.114 C

Explanation:

Given

Total 4.7 C is distributed in two spheres

Let q_1 and q_2 be the charges such that

q_1+q_2=4.7

and Force between charge particles is given by

F=\frac{kq_1q_2}{r^2}

4.7\times 10^11=\frac{9\times 10^9\times q_1\cdot q_2}{0.1^2}

q_1\cdot q_2=0.522

put the value of q_1

q_2\left ( 4.7-q_2\right )=0.522

q_2^2-4.7q_2+0.522=0

q_2=\frac{4.7\pm \sqrt{4.7^2-4\times 1\times 0.522}}{2}

q_2=0.114 C

thus q_1=4.586 C

3 0
3 years ago
A piece of metal has attained a velocity of 107.8 m/sec after fallinf for 10 seconds what is its initial velocity
soldi70 [24.7K]

Answer:

7.8 m/s

Explanation:

Here object is falling with a gravitational acceleration there  for we can take acceleration = 10 m/ s² and its constant through out the motion there for we can use motion equation

V = U + at

V - Final velocity

U - Initial velocity

a - acceleration

t - time

V=U+at

107.8=U + 10×10

  = 7.8 m/s

4 0
3 years ago
At the train station, you notice a large horizontal spring at the end of the track where the train comes in. This is a safety de
e-lub [12.9K]

Assume a maximum stopping acceleration of g/2 where g is acceleration due to gravity.

Answer:

2.99 m/s

Explanation:

Stopping distance, s = 3 ft = 0.914 m

final velocity, v = 0

a = g/2 = 4.9 m/s²

Use third equation of motion:

v^2-u^2 = 2as

substitute the values to find the speed of train:

0 -u^2 = 2\times -4.9 \times 0.914 \\u^2=8.96 \\u=2.99 m/s

6 0
3 years ago
How many electrons are in 204 C of charge?
zubka84 [21]

Answer:

The mass number 204 – 82 protons = 122 neutrons

Explanation:

Hope this helps!

5 0
3 years ago
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