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arsen [322]
3 years ago
5

Why are there graphs.

Mathematics
2 answers:
Tasya [4]3 years ago
8 0

Answer:

Graphs are a common method to visually illustrate relationships in the data. The purpose of a graph is to present data that are too numerous or complicated to be described adequately in the text and in less space. ... If the data shows pronounced trends or reveals relations between variables, a graph should be used.

Step-by-step explanation:

Rzqust [24]3 years ago
3 0

  • Is used to communicate a message that is contained in the shape of the data. (any patterns)
  • Is used to reveal relationship among many values

HOPE THSI HELPS!

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Question 6
inn [45]

Answer:

c

Step-by-step explanation:

4 times 2 is 8. 3 and 3 times -4 is -12

8 minus -12 is negative 4

7 0
3 years ago
Describe what the notation Upper P (Upper B vertical line Upper A )represents.
sergey [27]

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

Upper P (Upper B vertical line Upper A)

means

P(B|A)

It means that probability of getting event B given that Event A is occurred.

D. The probability of event B​ occurring, given that event A has already occurred. is also expressed as P(B|A)

Hence, Option 'D' is correct.

4 0
3 years ago
Duane is making cookies. The recipe calls for two times as many cups of sugar as butter, two times as many cups of oats as sugar
Tamiku [17]

Answer:

6.0

Step-by-step explanation:

: (2.0+(2.0+2.0)) = 6.0

6 0
3 years ago
1/3(4 + 18)-2²<br>PLIS I need help :(​
liraira [26]

Answer:

10/3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

1/3(4 + 18) - 2²

<u>Step 2: Evaluate</u>

  1. (Parenthesis) Add:                                                                                          1/3(22) - 2²
  2. Exponents:                                                                                                      1/3(22) - 4
  3. Multiply:                                                                                                           22/3 - 4
  4. Subtract:                                                                                                          10/3
5 0
3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
2 years ago
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