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noname [10]
3 years ago
7

Predict Note the type of reaction you expect for

Chemistry
2 answers:
Zinaida [17]3 years ago
8 0

Answer:

Combustion (and synthesis)

Explanation:

Edge 2021

Nadusha1986 [10]3 years ago
3 0

Answer:

it is a combustion reaction

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A source of zinc metal can be zinc ore containing zinc(II) sulfide. The ore is roasted in pure oxygen to produce the oxide and t
morpeh [17]

Answer:

32.7 grams of Zn will remained in the crucible after cooling.

Explanation:

2ZnS+3O_2 \rightarrow 2ZnO + 2SO_2..[1]

ZnO+C\rightarrow Zn+CO..[2]

Adding [1] + 2 × [2] we get:

2ZnS+3O_2+2C \rightarrow 2Zn + 2CO+2SO_2..[3]

Moles of ZnS in crucible = 0.50 mol

According to reaction [3]. 2 moles of ZnS gives 2 moles of Zn.

Then 0.50 moles of ZnS will give:

\frac{2}{2}\times 0.50 mol=0.50 mol of Zn.

Mass of 0.50 moles of Zn =

= 0.50 mol × 65.4 g/mol =32.7 g

32.7 grams of Zn will remained in the crucible after cooling.

5 0
4 years ago
If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T
Veronika [31]

Answer:

m_{MnO_2}=21.2gMnO_2

Explanation:

Hello,

In this case, given the balanced reaction:

2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-}  *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2

Best regards.

5 0
4 years ago
Give an example of an element that would be expected to share similar chemical properties with beryllium, calcium, and strontium
Aleks04 [339]
Strontium possibly but I’m not 100% sure
4 0
4 years ago
Symbiotic bacteria is not present in the nodules of: (a) gram plant (b) rice plant (c) sweet peas plant (d) peas plant.​
Vaselesa [24]

Answer:

B. Rice Plant

Explanation:

Symbiotic bacteria are present in nodules of cereal plants such as wheat.  Symbiotic bacteria are present in nodules of pod bearing plants such as peas, grams, etc.

4 0
3 years ago
Read 2 more answers
Use the reaction: 2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (g) + 5720 kJ. In the reaction, 200.0g of hydrocarbon react with
Sophie [7]

Answer:

9842kJ of energy are released

Explanation:

Based on the reaction:

2 C₄H₁₀ (g) + 13 O₂ (g) → 8 CO₂(g) + 10 H₂O (g) + 5720 kJ

<em>When 2 moles of C₄H₁₀ react with 13 moles of O₂ there are released 5720 kJ of energy</em>

As molar mass of C₄H₁₀ is 58.12g/mol, moles in 200.0g of the hydrocarbon are:

200.0g C₄H₁₀ ₓ (1mol / 58.12g) =<em> 3.441 moles of C₄H₁₀</em>

<em> </em>

As 2 moles of C₄H₁₀ release 5720kJ of energy, 3.441 moles of C₄H₁₀ release:

3.441 moles C₄H₁₀ ₓ (5720kJ / 2 moles C₄H₁₀) = <em>9842kJ of energy are released</em>

8 0
3 years ago
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