Answer:
0.0900 mol/L
Explanation:
<em>A chemist makes 330. mL of nickel(II) chloride working solution by adding distilled water to 220. mL of a 0.135 mol/L stock solution of nickel(II) chloride in water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits.</em>
Step 1: Given data
- Initial concentration (C₁): 0.135 mol/L
- Initial volume (V₁): 220. mL
- Final concentration (C₂): ?
- Final volume (V₂): 330. mL
Step 2: Calculate the concentration of the final solution
We prepare a dilute solution from a concentrated one. We can calculate the concentration of the working solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁/V₂
C₂ = 0.135 mol/L × 220. mL/330. mL = 0.0900 mol/L
The answer is: 4) " 2.7 * 10⁵ mg " .
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Explanation:
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Since all answer choices given are in "mg" ("milligrams"); we need to convert our given value, "0.27 kg" ("kilograms") to "mg" ("milligrams").
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Note the following "exact value" conversions:
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1000 mg = 1 g ;
1000 g = 1 kg.
(0.27 kg) (1000 g / 1 kg) (1000 mg/1 g) = __?__ mg ;
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The units of "kg", and "g" cancel to "1" and we are left with:
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0.27 * 1000 * 1000 mg = 270,000 mg = 2.7 * 10<span>⁵ </span> mg ; which is:
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→ Answer choice: # 4 .
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Answer:
The answer is tiny organisms known as cyanobacteria, or blue-green algae. These microbes conduct photosynthesis: using sunshine, water and carbon dioxide to produce carbohydrates and, yes, oxygen.
:-))
It protects the cell and allows certain material in and out of the cell
By not letting the sick run while doing other things like scrubbing dishes..
