Answer:
The table shows locations on a map.
<u>Place</u>
- park
- farmers market
- post office
- bus stop
<u>Location</u>
- (-2,2)
- (-2,3)
- (2, 2)
- (6,-3)
Which places on the map are 4 units apart?
O the park and the farmer's market
O the farmers market and the bus stop
<em><u>✓</u></em> <em><u>the post office and the park</u></em>
O the post office and the bus stop
Step-by-step explanation:
Distance :---

Step-by-step explanation:
We have got the lines :

Both lines intercept the x-axis in the point :

In all point from x-axis the y-component is equal to 0.

We replace the I point in the lines equations:

From the first equation :

From the second equation :

Then 
Finally :

y = ax + b and y = cx + d have the same x-intercept ⇔ad=bc
Yh can we please stop with all these links they don’t help at all
Answer:
Alright
Step-by-step explanation:
Bottom Left: Saturday
Bottom Right: Box A
Not sure about the top one :/
Answer: <em>
</em>
Step-by-step explanation:
<h3>
<em>
The complete exercise is:"A gardener has 27 tulip bulbs, 45 tomato plants, 108 rose bushes, and 126 herb seedlings to plant in the city garden. He wants each row of the garden to have the same number of each kind of plant. What is the greatest number of rows that the gardener can make if he uses all the plants?"</em></h3><h3 />
The first step to solve the exercise is to find the Greatest Common Factor (GCF) between 27, 45, 108 and 126.
You can follow these steps in order to find the GCF:
1. You must decompose 27, 45, 108 and 126into their prime factors:

2. You must multiply the commons with the lowest exponents. Then:
<em>
</em>
Therefore, the greatest number of rows that the gardener can make if he uses all the plants is:
