Answer:
Just in 1 dimension
Vpg = Vps + Vsg
Where
Vpg= relative to the ground
Vps= person relative to the ship
Vsg= ship relative to the ground
Vpg= Vps+Vsg ;
Vpg= 0.5 + 6
Vpg= 6,5 m/s
Answer:
The relation between velocity and time is a simple one during uniformly accelerated, straight-line motion. The longer the acceleration, the greater the change in velocity. Change in velocity is directly proportional to time when acceleration is constant.
~Hoped this helped~
~Brainiliest?~
11.46 meters
55 km/h = ? m/s
55 km/h × 1000 (meters per km) = 55,000 m/h
55,000 m/h ÷ 3,600 (seconds in an hour) = 15.28 m/s
15.28 m/s × 0.75 s = 11.46 m
Answer:
23.5 m/s
Explanation:
The velocity of the car in decelerated motion is given by
v = u + at
where
v = 0 is the final velocity
u is the initial velocity
a is the acceleration of the car
t = 3.0 s is the time it takes for the car to stop
The acceleration of the car is given by the frictional force, which is the only force acting on the car along the direction of motion, so:
where
is the coefficient of friction
Solving the previous equation for u, we find the initial velocity:
