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kkurt [141]
3 years ago
10

Which body could NOT be called a gas giant?

Physics
2 answers:
cestrela7 [59]3 years ago
6 0
Well, considering we are speaking of the planets in our solar system. There are 8 (9 if you like pluto
Not gas giants: mercury, Venus, earth, mars, Pluto.


Gas giants: Saturn, Jupiter, Uranus, Neptune.
Dafna11 [192]3 years ago
4 0
Sorry I don’t know but good luck and hope you find it
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An arrow is shot straight up in the air at an initial speed of 15 m/s. After how much time is the arrow heading downward at a sp
Greeley [361]

Answer:

2.35 seconds

Explanation:

Remark

This is a question where direction matters.  Let us call down + and up minus. It won't matter. The answer will be the same.

Formula

a = (vf - vi)/t

Givens

a = 9.8 m/s^2

vi = - 15 m/s

vf = 8m/s

Solution

9.8 = (8 - - 15)/t                 Multiply both sides by t

t * 9.8 = 23                       Divide by 9.8

t = 23/9.8

t = 2.35 s

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3 years ago
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Dmitriy789 [7]

Answer:

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6 0
3 years ago
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aleksley [76]
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6 0
3 years ago
A particle of mass m moves under a conservative force with potential energy V ( x )= cx/(x2+a2),where c and a are positive const
Anvisha [2.4K]

Answer:

The position of stable equilibrium is -a

And the period of small oscillations  must be: c/(ma^3)

Explanation:

Since the potential is:

V(x) = \frac{c x}{a^2+x^2}

We first look for a position of stable equilibrium. This posiiton must satisfy two considtions, that the first derivative of the potential must vanish at this point and the second derivative must be positive.

V'(x) = \frac{c}{a^2+x^2}-\frac{2 c x^2}{\left(a^2+x^2\right)^2}

Which vanish for

x = a   ; x =-a

The second derivative of V(x) is:

V''(x) = \frac{8 c x^3}{\left(a^2+x^2\right)^3}-\frac{6 c x}{\left(a^2+x^2\right)^2}

And:

V''(a) = -\frac{c}{2 a^3}\\V''(-a) = \frac{c}{2 a^3}\\

Therefore:

a)

The position of stable equilibrium is -a

And the period of small oscillations  must be:

\omega = \sqrt{2 V''(-a)/m} = \sqrt{\frac{c}{a^3 m}}

(c/(ma^3))^1/2

b)

Let's find the maximum amplitude if the particle starts at this point with velocity v

If this is the case, the total energy will be:

(mv^2)/2

And the maximum amplitude will be

x = a^3/c mv^2 = (m v^2 a^3)/ c

7 0
4 years ago
Isaac Newton experimented with prisms in 1666. What did his experiments show?
laiz [17]
I know the answer it’s …
6 0
3 years ago
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