w = wavelength Temperature = 23C w = 4 (L + 0.4 D) L = length of pipe v = f w D = diameter = 3 cm v = 331 + 0.6 T A variety of t
uning forks were placed over a closed pipe. The length of the pipe was adjusted by changing the water level. The length, L, was recorded when the pipe resonated with the tuning fork. Here are the frequencies and lengths. frequency Length 256 hz 32.5 cm 320 25.8 384 21.3 512 15.6 Calculate the wavelength from the length of the pipe. Calculate the speed from frequency and wavelength. Calculate the average speed and enter it in the associated quiz. Calculate the speed from the temperature and enter it in the quiz. Calculate the percent difference between the two speeds and enter it in the quiz.
1 answer:
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A) initial volume
We can calculate the initial volume of the gas by using the ideal gas law:
where
is the initial pressure of the gas
is the initial volume of the gas
is the number of moles
is the gas constant
is the initial temperature of the gas
By re-arranging this equation, we can find:
2) Now the gas cools down to a temperature of
while the pressure is kept constant:
, so we can use again the ideal gas law to find the new volume of the gas
3) In a process at constant pressure, the work done by the gas is equal to the product between the pressure and the difference of volume:
by using the data we found at point 1) and 2), we find
where the negative sign means the work is done by the surrounding on the gas.
We can calculate the initial volume of the gas by using the ideal gas law:
where
By re-arranging this equation, we can find
2) Now the gas cools down to a temperature of
while the pressure is kept constant:
3) In a process at constant pressure, the work done by the gas is equal to the product between the pressure and the difference of volume:
by using the data we found at point 1) and 2), we find
where the negative sign means the work is done by the surrounding on the gas.
Answer:
16200 J
Explanation:
t = Time the battery is on = 60 hours
I = Current =
Average voltage
Energy is given by
The energy delivered in the given time is 16200 J