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Artyom0805 [142]
4 years ago
13

w = wavelength Temperature = 23C w = 4 (L + 0.4 D) L = length of pipe v = f w D = diameter = 3 cm v = 331 + 0.6 T A variety of t

uning forks were placed over a closed pipe. The length of the pipe was adjusted by changing the water level. The length, L, was recorded when the pipe resonated with the tuning fork. Here are the frequencies and lengths. frequency Length 256 hz 32.5 cm 320 25.8 384 21.3 512 15.6 Calculate the wavelength from the length of the pipe. Calculate the speed from frequency and wavelength. Calculate the average speed and enter it in the associated quiz. Calculate the speed from the temperature and enter it in the quiz. Calculate the percent difference between the two speeds and enter it in the quiz.

Physics
1 answer:
Effectus [21]4 years ago
8 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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Can a body be said to be at rest and in motion at the same time?​
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A hydraulic cylinder causes the distance between points A and O to decrease at a constant rate of 3 inches per second. a) Determ
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Answer:

a) The speed of the slider is 4.28 in/s

b) The velocity vector is 2.33 in/s

Explanation:

a) According to the diagram 1 in the attached image:

r_{C/A} =12*cos55i-12*sin55j\\r_{C/A}=6.883i-9.829j

Also:

v_{C} =v_{A}+w_{AC}*r_{C/A}\\v_{Ci}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC} \\6.883&-9.829&0\end{array}\right]\\v_{Ci}=-3j+(0+9.829w_{AC} i-(0-6.883w_{AC})j\\v_{Ci}=9.829w_{AC}i+(-3+6.883w_{AC})j

If we comparing both sides of the expression:

-3+6.883w_{AC}=0\\w_{AC}=0.435rad/s

v_{C}=9.829*0.435=4.28in/s

b) According to the diagram 2 in the attached image:

r_{C/A}=12cos50i-12sin50j=7.713i-9.192j\\r_{B/C}=-3.856i+4.596j

v_{C}=v_{A}+w_{AC}r_{C/A}\\v_{C}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC}\\7.713&-9.192&0\end{array}\right] \\v_{Ci}=-3j+(9.192w_{AC})i+7.713w_{AC}j\\v_{Ci}=9.192w_{AC}i+(7.713w_{AC}-3)j

Comparing both sides of the expression:

7.713w_{AC}-3=0\\w_{AC}=0.388rad/s\\v_{C}=3.575i

v_{B}=v_{C}+w_{AC}r_{B/C}\\v_{B}=3.57i+\left[\begin{array}{ccc}i&j&k\\0&0&0.388\\-3.856&4.59&0\end{array}\right]  \\v_{B}=3.57i+(0-1.78)i-(0+1.499)j\\v_{B}=1.787i-1.499j\\|v_{B}|=\sqrt{1.787^{2}+1.499^{2}  } =2.33in/s

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